A)We have been given →
Hieght of trough = 5m
length of trough = 6m
Breadth of trough = 4m
so , As the top is opened for feeding animals.
Area of base = length× Breadth
= (6×4) m²
= 24 m²
Area of Front and back face = Hieght × length
= (5×6) m²
= 30m²
Area of side faces = hieght × Breadth
= (5×4) m²
= 20 m²
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B)Total Surface area of trough will be given by formula - 2(lb+bh+hl)
= 2{(6×4)+(4×5)+(5×6)}
= 2{24+20+30}
= 2×74
= 148 m²
As we have been told top is open , so we will deduct top from Total surface Area to obtain Surface area →
(148-24) m²
(Area of top will be same as base area , that is 24m² as we have solved in A)
= 124m²
Answer→ Surface area of trough is 124m²
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Answer:
broad sense heritability = 0.75
Step-by-step explanation:
Step 1: Variables
phenotypic variation (Vp)
genotype variation (Vg)
environment variation (Ve)
broad sense heritability (H)
Step 2: Formulas:
H = Vg / Vp
Vp = Vg + Ve
Vg = Vp - Ve
Step 3: Given data
Vp = 20
Ve = 5
Step 4: Computation
Vg = 20 - 5 = 15
H = 15 / 20
H = 0.75
Hope this helps!
Answer:
vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv=kkkkk
Step-by-step explanation:
Answer:
x=16
Step-by-step explanation:
Because of Thales Intercept Theorem, AN/NG=NE/GL
NE/GL=1/2, AG=2x-9+x+7=3x-2
2x-9/3x-2=1/2
x=16
Answer:
G, 113.04
Step-by-step explanation:
To find the area of the head of the nail you need to use the*
> A= π*r^2* A equals area, π equals pi(3.14) and then you square your raidius, which is 6 in your case.
π*r^2
plug in your six as the *r
π*6*^2
solve 6^2=36 and multiply that by your π which is 3.14
3.14*36
=113.04
Hope that helped!! :)
