P(1) = P(0) [exp (rt)]
9,800 = 10,000 (0.98)^1
r = loge<span> (0.98) = ln (0.98) = -0.0202
</span>
<span>P(t) = P(0)[exp(-0.0202t)]</span>
The result of an absolute value operation is never negative. So the smallest that the expression |x+5| can be is 0.
Tacking on "-8" to |x+5| leads to |x+5|-8
The range of this is [-8, infinity) since the smallest |x+5|-8 can be is -8. All I did was subtract 8 from the smallest value of |x+5|
Final Answer: choice C)
