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VikaD [51]
3 years ago
5

PLEASE HELP!!!! IMA DESPRATE!!!!!!!!Find the second term in the sequence defined by an = −5(n2 + 1n).

Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0

The second term of the given sequence aₙ = -5(n² + 1n) when solved gives us; a₂ = -20

<h3>How to find the nth term of a sequence?</h3>

We are given the formula for a sequence as;

aₙ = -5(n² + 1n)

Where n is the position of the term.

Now, for the first term, we will have;

a₁ = -5(1² + 1(1))

a₁ = -10

The second term of the sequence is;

a₂ = -5(2² + 1(2))

a₂ = -20

Read more about Sequence at; brainly.com/question/6561461

#SPJ1

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She drunk about 

9 and 3/4 of her water

hope this helps :3

3 0
4 years ago
A plumber charges $70 per hour plus $40 dollars for the call. What does he charge for 4 hours of work
Varvara68 [4.7K]
First, let's create an equation for this problem. 
($70 × 4) + $40

Now, all you would have to do is solve it using the order of operation (PEMDAS).
($70 × 4) + $40 = $280 + $40
$280 + $40 = $320

The plumber charged $320. 

I hope this helps!
8 0
4 years ago
Read 2 more answers
Which procedure justifies whether -3x(5-4)+3(x-6) is equivalent to -12x-6?
DENIUS [597]

Answer:

Step-by-step explanation:

-3x(5-4) + 3(x-6)

-15x + 12 + 3x - 18

-15x + 3x +12 - 18

-12x - 6

4 0
3 years ago
Read 2 more answers
Solve for the <br> variable 8=2(x-5)+6x
shutvik [7]

Answer:

x=2.25

Step-by-step explanation:

  • 8=2(x-5)+6x
  • 8=2x-10+6x
  • 8+10=2x+6x
  • 18=8x
  • 18/8=x
  • 2.25=x
5 0
3 years ago
80. You buy a new car for $24,000. At the end of n years, the value of your car is given by the sequence: an=24000(3/4)n, n=1, 2
kipiarov [429]

Answer:

The value at the end of the fifth year (a5) is equal to $5,696.

As the number of years n is the exponent of a number that is smaller than 1, the value of the car is decreasing with the years.

We also can conclude that the value of the car decreases 25% each year.

Step-by-step explanation:

The value of the car is represented by an=24000(3/4)^n, where n is the year.

The value at the end of the fifth year (a5) is equal to:

a_5=24,000\left(\dfrac{3}{4}\right)^5=24,000*0.2373=5,695

As the number of years n is the exponent of a number that is smaller than 1, the value of the car is decreasing with the years.

We also can conclude that the value of the car decreases 25% each year:

a_n/a_{n-1}=(3/4)^{n-(n-1)}=(3/4)^1=0.75

4 0
3 years ago
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