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RSB [31]
2 years ago
8

What is the simplest form of 34/42

Mathematics
2 answers:
vfiekz [6]2 years ago
7 0
17/21 you just have to find the highest common factor, which in this case, is two
gtnhenbr [62]2 years ago
3 0
Divide by 2 - 17/21

is it divisible by anything else?
No, because 17 is a prime number, therefore it cannot be divided further.

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Find the values of x work 10% of my grade
Ostrovityanka [42]

Answer:

x = 35

Step-by-step explanation:

1. Add all angles

115+(x+36)+24+(2x+10)+2x

= 5x+185

2. Match 360 and fix

5x+185=360

5x=360-185

5x=175

x=175/5

x=35

Hope this helps

6 0
2 years ago
Read 2 more answers
Write a polynomial function in standard form with zeros at 0, 1, and 2.
BARSIC [14]

Answer:

Step-by-step explanation:

f(x)=(x-0)(x-1)(x-2)

=x(x^2-3x+2)

or f(x)=x^3-3x^2+2x

3 0
3 years ago
50 POINTS IF YOU ANSWER CORRECTLY!
melisa1 [442]

Answer:

<u>Problem 4:</u>  Option C, 32

<u>Problem 5:</u>  You need to have the 2 and the x combine.  Make the table 2x than 16.

<u>Problem 6:</u>  x = 17

<u>Problem 7:</u>  She drew a 2, x and an 16.  Instead you must have 2x and 16.  2x + 16 = 50

Step-by-step explanation:

<u>Problem 4</u>

2 + x + 16 = 50

x + 18 - 18 = 50 - 18

x = 32

Answer:  Option C, 32

<u>Problem 5</u>

You need to have the 2 and the x combine.  Make the table 2x than 16.

Answer:  You need to have the 2 and the x combine.  Make the table 2x than 16.

<u>Problem 6</u>

2x + 16 - 16 = 50 - 16

2x / 2 = 34 / 2

x = 17

Answer:  x = 17

<u>Problem 7</u>

She drew a 2, x and an 16.  Instead you must have 2x and 16.  2x + 16 = 50

Answer: She drew a 2, x and an 16.  Instead you must have 2x and 16.  2x + 16 = 50

4 0
3 years ago
Read 2 more answers
What is the slope of the line perpendicular to the y=-1/5x-9? <br><br> Plz help me
labwork [276]

Answer:

5

Step-by-step explanation:

Remember that the slope of a line that is perpendicular to a given line is the negative reciprocal of the slope of the given line.

Here we are given the line y = -(1/5)x - 9.  The slope is (-1/5).  The negative reciprocal of this is +5.  That's the answer you wanted.

4 0
3 years ago
Solve the following system of equation
krok68 [10]

Answer:

x = 6 , y = -4 , Z = -1

Step-by-step explanation:

Solve the following system:

{2 x + 3 y - Z = 1 | (equation 1)

3 x + y + 2 Z = 12 | (equation 2)

-3 + x + 2 y = -5 | (equation 3)

Express the system in standard form:

{2 x + 3 y - Z = 1 | (equation 1)

3 x + y + 2 Z = 12 | (equation 2)

x + 2 y+0 Z = -2 | (equation 3)

Swap equation 1 with equation 2:

{3 x + y + 2 Z = 12 | (equation 1)

2 x + 3 y - Z = 1 | (equation 2)

x + 2 y+0 Z = -2 | (equation 3)

Subtract 2/3 × (equation 1) from equation 2:

{3 x + y + 2 Z = 12 | (equation 1)

0 x+(7 y)/3 - (7 Z)/3 = -7 | (equation 2)

x + 2 y+0 Z = -2 | (equation 3)

Multiply equation 2 by 3/7:

{3 x + y + 2 Z = 12 | (equation 1)

0 x+y - Z = -3 | (equation 2)

x + 2 y+0 Z = -2 | (equation 3)

Subtract 1/3 × (equation 1) from equation 3:

{3 x + y + 2 Z = 12 | (equation 1)

0 x+y - Z = -3 | (equation 2)

0 x+(5 y)/3 - (2 Z)/3 = -6 | (equation 3)

Multiply equation 3 by 3:

{3 x + y + 2 Z = 12 | (equation 1)

0 x+y - Z = -3 | (equation 2)

0 x+5 y - 2 Z = -18 | (equation 3)

Swap equation 2 with equation 3:

{3 x + y + 2 Z = 12 | (equation 1)

0 x+5 y - 2 Z = -18 | (equation 2)

0 x+y - Z = -3 | (equation 3)

Subtract 1/5 × (equation 2) from equation 3:

{3 x + y + 2 Z = 12 | (equation 1)

0 x+5 y - 2 Z = -18 | (equation 2)

0 x+0 y - (3 Z)/5 = 3/5 | (equation 3)

Multiply equation 3 by 5/3:

{3 x + y + 2 Z = 12 | (equation 1)

0 x+5 y - 2 Z = -18 | (equation 2)

0 x+0 y - Z = 1 | (equation 3)

Multiply equation 3 by -1:

{3 x + y + 2 Z = 12 | (equation 1)

0 x+5 y - 2 Z = -18 | (equation 2)

0 x+0 y+Z = -1 | (equation 3)

Add 2 × (equation 3) to equation 2:

{3 x + y + 2 Z = 12 | (equation 1)

0 x+5 y+0 Z = -20 | (equation 2)

0 x+0 y+Z = -1 | (equation 3)

Divide equation 2 by 5:

{3 x + y + 2 Z = 12 | (equation 1)

0 x+y+0 Z = -4 | (equation 2)

0 x+0 y+Z = -1 | (equation 3)

Subtract equation 2 from equation 1:

{3 x + 0 y+2 Z = 16 | (equation 1)

0 x+y+0 Z = -4 | (equation 2)

0 x+0 y+Z = -1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{3 x+0 y+0 Z = 18 | (equation 1)

0 x+y+0 Z = -4 | (equation 2)

0 x+0 y+Z = -1 | (equation 3)

Divide equation 1 by 3:

{x+0 y+0 Z = 6 | (equation 1)

0 x+y+0 Z = -4 | (equation 2)

0 x+0 y+Z = -1 | (equation 3)

Collect results:

Answer:  {x = 6 , y = -4 , Z = -1

6 0
3 years ago
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