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blagie [28]
2 years ago
6

There are 10 participants in the Olympic 100 meter sprint. If first, second, and third place get medals, how many possible outco

mes of medal winners are there if Usain Bolt places first?
Mathematics
1 answer:
BlackZzzverrR [31]2 years ago
8 0

Answer:
56

Step-by-step explanation:

with Usain Bolt getting the the first place there is only 9 other contestants that can get the two other available medal position. When the second place is taken, there will be 8 remaining contestants for a third place therefore you do 9 multiplied by 8 to get 56 differrent combinations of contestants for the third or second place medal

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Sunscreen is priced at $10.00 per bottle, plus 8% tax. If Sonya purchases a bottle of sunscreen with a $20.00 bill, then what is
MatroZZZ [7]

Answer:

$9.20

Step-by-step explanation:

the tax would be $0.80 because 8% of $10 is $0.80

so the total cost is $10.80

now subtract that by her $20 bill

20-10.80= 9.20

so she will be given $9.20 back in change

hope this helps luv <3

5 0
3 years ago
Read 2 more answers
Strange math is confusing to me :P pls help
Rasek [7]

Answer: look at the inches foots and miles and figure our the matht that would go along with it.

Step-by-step explanation: i did it but no telles hop this helps

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6 0
3 years ago
Using an infinite geometric series for the repeating decimal 0.551¯¯¯¯¯¯¯¯, with ratio 11000, find integers a and b so that 0.55
irga5000 [103]

Answer:

Sum = 551/999

Where a = 551 and b = 999

The two integers are 551 and 999

Step-by-step explanation:

Given

Decimal = 0.551

Ratio = 1/1000

By repeating the decimal, we can write;

0.551 -bar = 0.551551551.....

0.551551551..... = 0.551 + 0.000551 + 0.000000551 + ....

= 551/1000 + 551/1000000 + 551/1000000000 + ......

= 551/10³ + 551/10^6 + 551/10^9 + .....

= n=0 Σ∝(551/10³)(1/10³)^n

Hence, the infinite geometrc series is Σ(551/10³)(1/10³)^n for n = 0 to

∝

Given the ratio of 1/1000

Let r = 1/1000

r = 1/10³

a = 551/10³

The sum is defined as follows;

a/(1-r)

Sum = 551/10³ / (1 - 1/10³)

Sum = 551/1000 ÷ 999/1000

Sum = 551/999

So, a/b = 551/999

Where a = 551 and b = 999

The two integers are 551 and 999

5 0
3 years ago
It’s giving me symbols to add
Natalija [7]

Answer:

I. Ella packed 70 books more than Ray.

II. Ray packed 580 books.

III. Ella packed 650 books.

Step-by-step explanation:

Given the following data;

Ray = 29 boxes of 20 books

Ella = 26 boxes with 25 books

To find the total number of books packed by Ray;

Total for Ray (Ray packed) = 29 * 20

Total for Ray = 580 books.

To find the total number of books packed by Ella;

Total for Ella (Ella packed) = 26 * 25

Total for Ella = 650 books.

Next, we find the difference between the books packed by Ella and Ray;

Difference = Ella - Ray

Difference = 650 - 580

Difference = 70 books

5 0
3 years ago
Solve with elimination:<br> -2x - 4y = 8<br> -6x +24 = 12y
Elanso [62]

Ohh, Elimination Im doing that XD So its

Anwser - No Solution

8 0
3 years ago
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