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pantera1 [17]
3 years ago
13

Find the value of p when p = 2q +4r when q = -4 and r = 5

Mathematics
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

p= 12

Step-by-step explanation:

p= 2(-4) + 4(5)

= -8 +20

= 12

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x = 2 and y = 1

Step-by-step explanation:

A) 5x+y=11

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A) 5x + (x -1) = 11. 6x-1=11. 6x = 11+1

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7 0
3 years ago
PLEASE HELP ME WITH THIS QUESTION ITS URGENT!!!
Alex Ar [27]

Start by distributing the exponent to each of the terms in (2u)^{3}.  This will become 2^{3} u^{3}, and 2^{3} =8.  Now, the expression is:

\frac{2u^{3} v^{2} }{8u^{3} * u^{2} }.


We can now simplify the bottom to read: 8u^{5} because when multiplying variables raised to an exponent, we add the exponents.  The expression now looks like:

\frac{2u^{3} v^{2} }{8u^{5} }


The 2/8 simplifies to 1/4:

\frac{u^{3} v^{2} }{4u^{5} }


Now, we have two u terms on the top and bottom.  When dividing variables raised to an exponent, we subtract the exponents.  However, since 3-5=-2, the term will be on the bottom to avoid the negative exponent.  The final answer is:

\frac{v^{2} }{4u^{2} }


Hope this makes sense!!


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4 years ago
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