X=5
y=6
here’s how i got it:
-6x+6y=6
-6x+3y=-12
multiply the second equation by -1
you will get this:
-6x+6y=6
6x-3y=12
add them up and you will get
y=6
then substitute y in one of the equations and you will get x=5
Answer:
19.
log9(5x^2 + 10) - log9(10) = 1
<=> log9((5x^2 + 10)/10) = log9(9)
<=> (5x^2 + 10)/10 = 9
<=> 5x^2 + 10 = 90
<=> 5x^2 = 80
<=> x^2 = 16
<=> x = +/- (4)
20.
log5(2x^2 + 4) + log5(3) = 2
<=> log5((2x^2 + 4) x 3) = log3(9)
<=> 6x^2 + 12 = 9
<=> 6x^2 = -3
=> No real x satisfies. ( x^2 always larger or equal to 0)
21.
log6(8) + log6(7 - 2x^2) = 2
<=> log6(8 x (7 - 2x^2)) = log6(36)
<=> 56 - 16x^2 = 36
<=> 16x^2 = 20
<=> x^2 = 5/4
<=> x = +/- sqrt(5/4)
Hope this helps!
:)
Answer:
The answer is 37 200.
Step-by-step explanation:
The steps are :
x² - y² = (x + y)(x - y)
193² - 7² = (193 + 7)(193 - 7)
= (200)(186)
= 37 200
