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3 years ago

Solve each equation. Round your answers to the nearest ten-thousandth. Please show work. Part 3A

Mathematics

1 answer:

Butoxors [25]3 years ago

5 0

Answer:

19.

log9(5x^2 + 10) - log9(10) = 1

<=> log9((5x^2 + 10)/10) = log9(9)

<=> (5x^2 + 10)/10 = 9

<=> 5x^2 + 10 = 90

<=> 5x^2 = 80

<=> x^2 = 16

<=> x = +/- (4)

20.

log5(2x^2 + 4) + log5(3) = 2

<=> log5((2x^2 + 4) x 3) = log3(9)

<=> 6x^2 + 12 = 9

<=> 6x^2 = -3

=> No real x satisfies. ( x^2 always larger or equal to 0)

21.

log6(8) + log6(7 - 2x^2) = 2

<=> log6(8 x (7 - 2x^2)) = log6(36)

<=> 56 - 16x^2 = 36

<=> 16x^2 = 20

<=> x^2 = 5/4

<=> x = +/- sqrt(5/4)

Hope this helps!

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75 percent

Step-by-step explanation:

percent increase = increase/original ×100

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2 years ago

While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at

tekilochka [14]

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>

Let x be the speed of the walkway.

(2.8 + x) = speed of child moving in direction of the walkway

(2.8 - x) = speed of child moving against the direction of the walkway

Travel time = distance/speed

Travel time of child moving in direction of walkway = 23/(2.8+x)

Total elapsed time given = 29s

23/(2.8 + x)+ 23 / (2.8-x) = 29

LCD = (2.8 + x)(2.8 - x)

$23(2.8 - x) + 23(2.8 + x) = 29(2.8 + x)(2.8 -x)$

simplifying the equation, we get

$23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)$

$23(2.8+2.8)/29=2.8^2-x^2$

$x^2=(2.8)^2-(23*5.6)/29)=3.4$

$x=\sqrt{3.4}=1.84m/s$

Speed of walkway = 1.84 m/s

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

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1 year ago

the US Census found at the population per square mile in the state rose from 128.7 to 191.3 during the last 10 years. By how muc

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Answer:

The population growth is 6.26 per square mile per year

Step-by-step explanation:

We are given

he US Census found at the population per square mile in the state rose from 128.7 to 191.3 during the last 10 years

So,

Initial population =128.7

Final Population =191.3

Total time =10 years

now, we can find population grow per year

$=\frac{final-initial}{T}$

now, we can plug values

$=\frac{191.3-128.7}{10}$

$=6.26$

So,

The population growth is 6.26 per square mile per year

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3 years ago

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2 years ago

the price of the cell phone is expected to increase by 165% in September 2015. The current price of a cell phone is $62.80. What

Sladkaya [172]

Answer:

$166.42.

Step-by-step explanation:

We have been given that the price of the cell phone is expected to increase by 165% in September 2015. The current price of a cell phone is $62.80.

The price of cell phone in September 2015 will be $62.80 plus 165% of $62.80.

$\text{The predicted cost of a cell phone in September 2015}=\$62.80+(\frac{165}{100}*\$62.80)$

$\text{The predicted cost of a cell phone in September 2015}=\$62.80+(1.65*\$62.80)$

$\text{The predicted cost of a cell phone in September 2015}=\$62.80+\$103.62$

$\text{The predicted cost of a cell phone in September 2015}=\$166.42$

Therefore, the predicted cost of a cell phone in September 2015 will be $166.42.

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3 years ago

Solve each equation. Round your answers to the nearest ten-thousandth. Please show work. Part 3A​

Solve each equation. Round your answers to the nearest ten-thousandth. Please show work. Part 3A