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1 year ago

Write an equation that goes through the point (2,-3) with a slope of -3

Mathematics

1 answer:

uysha [10]1 year ago

7 0

Answer:

Point slope:y - y1 = m(x -x1)y - y1 = m(x -x1)

Given values: (x1 , y1) = (2 , 3)m = 3

Solution: y - 3 = 3(x - 2

Step-by-step explanation:

hope this helps if not let me know have a good day

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Or

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2 years ago

What is the value of the 5 in the number 14.5?

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3 years ago

What are the amplitude, period, and phase shift of the given function? f(t)=-2/3 cos (3t-3pi)

dybincka [34]

Answer:

amplitude; $\frac{2}{3}$

Phase shift; $\pi$ units right

Period; $\frac{2\pi}{3}$

Step-by-step explanation:

The given function is

$y=-\frac{2}{3}\cos(3t-3\pi)$

This function is of the form;

$y=A\sin (Bt+C)$

The period is given by:

$|A|=|-\frac{2}{3}|= \frac{2}{3}$

The period is given by:

$T=\frac{2\pi}{|B|}= \frac{2\pi}{|3|}=\frac{2\pi}{3}$

The phase shift is given by;

$\frac{C}{B}=\frac{-\3pi}{3}=- \pi$ or $\pi$ units right.

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