Find all angles θbetween 0° and 2pi satisfying the given equation ? sin(θ)=2√2

1 answer:

4 0

We are to determine all angles between 0° and 2pi satisfying the given equation sin(θ) = 2√2. The answer is that no angles that would fit to the given equation. This is because the values of trigonometric functions such as cosine and sine do not go more than 1. Since 2√2 is equal to 2.83, then the answer is none.

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