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solmaris [256]
2 years ago
6

A group of friends were working on a student film. They spent $949 on equipment, which was 73% of their total budget. What was t

he total budget for their student film?
Mathematics
2 answers:
wlad13 [49]2 years ago
7 0

Answer:

\huge\boxed{\sf x = \$ 1300}

Step-by-step explanation:

Let the total budget be x.

<u>Given condition:</u>

73% of total budget = 949

73% of x = 949

<u>Key:</u>

of => to multiply

% => out of 100

<u>Solution;</u>

\displaystyle \frac{73}{100} \times x = 949\\\\Multiply \ \frac{100}{73} \ to \ both\ sides\\\\x=949 \times \frac{100}{73} \\\\x = \frac{94900}{73} \\\\x = \$ 1300\\\\\rule[225]{225}{2}

Annette [7]2 years ago
3 0

Answer:

$1300

Step-by-step explanation:

Let the total budget be x.

According to the question they spent

73% of their total budget i.e $949

  • 73% of x = $949
  • 73/100 × x = 949
  • x = 949 × 100/73
  • x = 1300

∴ the total budget for their student film was $1300.

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3 years ago
The sides of two regular octagons are 3 in. And 6 in. respectively. Find the ratio of their perimeters and their areas
photoshop1234 [79]

The ratio of their perimeters is \frac{1}{2} and the ratio of their areas is \frac{1}{4}

Step-by-step explanation:

A regular n-side polygon has

  • n equal sides
  • n equal angles
  • The measure of each interior angle = \frac{(n-2).180}{n}
  • Its perimeter = n × a, where a is the length of its side

<em>V.I.Note: all regular polygons have same number of sides are similar, because their interior angles are equal in measures and their sides are proportion</em>

<em />

∵ There are to regular octagons

- Regular octagon has 8 equal sides and 8 equal angles

∴ The two octagon are similar

∵ Their sides are 3 inches and 6 inches

∴ The constant ratio between their sides = \frac{3}{6}

- Divide the two terms of the ratio by 3 to simplify it

∴ The constant ratio between their sides = \frac{1}{2}

In similar figures <em>the ratio between their perimeters is equal to the constant ratio between their sides</em>, and <em>the ratio between their areas is equal to square the constant ratio between their sides</em>

∵ The two octagons are similar

∵ The constant ratio between their sides = \frac{1}{2}

∵ The ratio between their perimeters = the constant ratio between

   their sides

∴ The ratio between their perimeters = \frac{1}{2}

∵ The ratio between their areas = (constant ratio)²

∴ The ratio between their areas = (\frac{1}{2})^{2}=\frac{1}{4}

The ratio of their perimeters is \frac{1}{2} and the ratio of their areas is \frac{1}{4}

Learn more:

You can learn more about the polygons in brainly.com/question/3779181

#LearnwithBrainly

6 0
3 years ago
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Four students equally share 1\4 poud of peanuts.How of a pound of peanuts did each student get?
posledela

Answer:1/16

Step-by-step explanation:1/4= .25

Divide .25 by 4( for the four students) = .0625

.0625 is equivalent to 1/16

4 0
3 years ago
The explicit formula for an arithmetic sequence is an = 20 + (n − 1)(2). What is the 200th term?
Andrews [41]

Answer:

a_{200}=418

Step-by-step explanation:

The explicit formula for an arithmetic sequence is given by :

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We need to find the 200th term of the sequence.

Put n = 200 in equation (1)

a_{200}=20+(200-1)2\\\\=20+199\times 2\\\\=418

So, the 200th term of the sequence is 418.

7 0
3 years ago
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