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Blababa [14]
3 years ago
6

drako found an emarald in a cave at a depth between negative 1\2 and negative 1 2\3 meters. Which number could represent the dep

th at which the emerald is located ?
Mathematics
1 answer:
Delvig [45]3 years ago
6 0

Answer:

(-\frac{7}{6} )

Step-by-step explanation:

From the question the emerald was located at a depth which is between -1/2 and -1 2/3 meters

This statement can be written as

(-1\frac{2}{3}) -(-\frac{1}{2} )

To get the depth, you find the depth of the emerald location, you find difference between the two mentioned depths

-(1\frac{2}{3} )-(-\frac{1}{2} )\\\\

Change first term to improper fraction

=-(\frac{5}{3} )-(-\frac{1}{2} )\\\\

Find the LCM to solve the operation the involves the fractions.The Least common multiple here is 6 i.e 3*2

=(-\frac{5}{3} )-(-\frac{1}{2})\\

=\frac{-5}{3} +\frac{1}{2} =\frac{-10+3}{6} =\frac{-7}{6}

The number that could represent the depth at which the emerald was located is

=\frac{-7}{6}

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Step-by-step explanation:

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Hope I could help!!! Good luck!!!

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3 years ago
A researcher has two percentages and wants to know if the percentages are statistically different. The researcher calculates the
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Answer:

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And we can use the following excel code to find it:"=2*(1-NORM.DIST(4.21,0,1,TRUE)) "

With the p value obtained and using the significance level assumed for example\alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the percentage 1 is significantly different from the percentage 2.

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Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 = \mu_2  

Alternative hypothesis: \mu_1 \neq \mu_2  

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Alternative hypothesis: \mu_1 -\mu_2\neq 0  

Where \mu_1 and \mu_2 represent the percentages that we want to test on this case.

The statistic calculated is on this case was Z=4.21. Since we are conducting a two tailed test the p value can be founded on this way.

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And we can use the following excel code to find it:"=2*(1-NORM.DIST(4.21,0,1,TRUE)) "

With the p value obtained and using the significance level assumed for example\alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the percentage 1 is significantly different from the percentage 2.

And the best option on this case would be:

 D) Are statistically different.

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3 years ago
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