first, find the numeric value for 11/15
second to find theta, simply do the <em>inverse</em> cos (which is cos^-1) of the first answer.
now you know theta, just do the sin of 90 - theta and that's it!
since you know whatr cos(theta) is, you just take the inverse cos of that number to get theta and 'reverse' cos, essentially. you are just solving for theta, by reversing the cos function with cos^-1
please mark as brainliest!
check the transformation template below, hmmm so to get the graph of "y" move to the right by 1 unit, we can simply make C = -1.
now, the x-intercept is simply where the graph touches the x-axis, and when that happens y = 0, so
![\begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad a^{log_a x}=x\leftarrow \textit{let's use this rule} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{y}{0}~~ = ~~\log_2(x-1)\implies 2^0=2^{\log_2(x-1)}\implies 2^0=x-1 \\\\\\ 1=x-1\implies 2=x~\hspace{10em}\stackrel{x-intercept}{(2~~,~~0)}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bllll%7D%20%5Ctextit%7BLogarithm%20Cancellation%20Rules%7D%20%5C%5C%5C%5C%20log_a%20a%5Ex%20%3D%20x%5Cqquad%20%5Cqquad%20a%5E%7Blog_a%20x%7D%3Dx%5Cleftarrow%20%5Ctextit%7Blet%27s%20use%20this%20rule%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7By%7D%7B0%7D~~%20%3D%20~~%5Clog_2%28x-1%29%5Cimplies%202%5E0%3D2%5E%7B%5Clog_2%28x-1%29%7D%5Cimplies%202%5E0%3Dx-1%20%5C%5C%5C%5C%5C%5C%201%3Dx-1%5Cimplies%202%3Dx~%5Chspace%7B10em%7D%5Cstackrel%7Bx-intercept%7D%7B%282~~%2C~~0%29%7D)
Answer: A
Step-by-step explanation:
(Friend 1, Friend 2)
Friend 1 = x
Friend 2 = y
(x, y) variables are substitution for the flavors
So it cant be C or D
B doesn't have all the possible solutions
30w + 20g 
2400
In this equation, the number of wreaths is represented with the variable 'w', and the number of garlands is represented the equation 'g'
Since the band only has to make at least 2400, the amount of money made must be equal to or more than 2400.
Good luck!
