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Gwar [14]
2 years ago
11

Answer 25 questions from any subject to get 400 pts ill give 25% and branliest

Mathematics
1 answer:
sladkih [1.3K]2 years ago
6 0
17.55 dollars for every single
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Please see attached pic
kirza4 [7]
The answer is D!
hopefully this helps
8 0
3 years ago
There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of
Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta (1)

Where:

AC - The distance from A to C, measured in miles.

AB - The distance from A to B, measured in miles.

BC - The distance from B to C, measured in miles.

\theta - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta

\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}

\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right) (2)

If we know that BC = 7\,mi, AB = 8\,mi, AC = 5\,mi, then the bearing from island B to island C:

\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]

\theta \approx 38.213^{\circ}

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0
3 years ago
Help me, this is math and I need to this this extension.
Gnom [1K]

Applying pythagorean theorem:-

\\ \sf\longmapsto 8^2-5^2=b^2

\\ \sf\longmapsto 64-25=b^2

\\ \sf\longmapsto b^2=39

\\ \sf\longmapsto b=\sqrt{39}

\\ \sf\longmapsto b=6.24

5 0
3 years ago
Read 2 more answers
Plz help! Don’t understand this question
solniwko [45]

Answer:

11.91

Step-by-step explanation:

The question says there is a new line that connects V and T. If this line is drawn, the diagram would have a right-angle triangle. This triangle is called TUV.

In triangle TUV, the side length created by the points VT is the hypotenuse.

For right-angle triangles, you can use the Pythagorean theorem to find any side.

It's in the format side² + side² = hypotenuse².

To use the formula, you need to know the length of the other two sides. The length of these sides, because they are exactly horizontal or vertical, is found by subtracting the smaller coordinate from the other (that is not the same).

The lengths of other sides:

VU:

-3 is the same. The length is 3.5 - (-5.75) = 9.25

UT:

-5.75 is the same. The length is 4.5 - (-3) = 7.5

Substitute the lengths into the Pythagorean theorem:

a² + b² = c²

9.25² + 7.5² = c²  Simplify

141.8125 = c²  Find the square root of both sides to isolate c

c = 11.91  Final answer, length of VT

7 0
3 years ago
Charisse is buying two different types of cereals from the bulk bins at the store. Granola costs $2.29 per pound and muesli cost
valentina_108 [34]
Even though im not giving you grapahs, I can explain you the situation and I can shed you light inot this. Pay attention. Giveen the data we are going to use it like this  <span>2.29x + 3.75y <= 7.00. Remember, you can't spend more money than 7.00, so whatever you buy has to be within 7.00$ or equal 7.00$. Since you're buying in pounds, and the amount varies, you have a variable there to indicate the price of each product depending on how many pounds of it you buy. Now, what you need to do is use this equation to graph and also solving part b by substituting in that value for y. I hope this can help you</span> 
6 0
4 years ago
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