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AlladinOne [14]
3 years ago
6

5 2/3 - 2 5/6 how much is this

Mathematics
2 answers:
Bond [772]3 years ago
6 0

if those are fractions being five and two thirds etc... I believe it would be 17/6. if you convert to improper fractions and then get a common denominator to subtract that should do it. Hope that helps.

Phantasy [73]3 years ago
5 0
This is a super typical question in fractions but i'm sure you are good at it. Anyway the answer is 2 5/6. Hope my answer helps you.
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If NS bisects QNR find the measure of QNR
maksim [4K]

both angles would equal the same so you have:

6x-57 = 2x+15

add 57 to each side:

6x = 2x+72

subtract 2x from each side:

4x = 72

 divide:

x = 72/4 = 18


now replace x with 18:


6(18) - 57 = 51

2(18) +15 = 51

51 +51 = 102

Angle QNR = 102 degrees


7 0
3 years ago
The value of x-y is negative, and x and y are both positive. What can you conclude about the values of x
Stolb23 [73]
Well for two positive numbers subtracted to equal a negative number, the first number must have a value that is less than the second number. (Ex. 3-4= -1) In this case, you can conclude that x is less than y! (x<y)
3 0
3 years ago
Jessica has 20 pieces of candy in a bag: 2 mint sticks, 9 jelly treats, and 9 fruit tart chews. If she eats one piece every 10 m
dedylja [7]

Answer:

18.95%

Step-by-step explanation:

In this case what we must do is calculate the probability of eating a jelly treats first and then another jelly treats, being the final probability the multiplication of these events.

We know that there are 20 in total and that initially there are 9 jelly treats, so the first event is the probability:

9/20  

And the second event, with one less in each, would be:

8/19

The final probability then:

9/20 * 8/19 = 0.1895

So the probability of this happening is 18.95%

4 0
3 years ago
Read 2 more answers
How do i do 3 part a ?
WINSTONCH [101]


In general the binomial expansion is


(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0


So in our case, because we want ascending powers of x we'll write,


(-3x + 1)^{11} =  {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9  + {11 \choose 3 } (-3x)^3 1^8 + ...


We need to calculate the binomial coefficients:


{11 \choose 0}  = 1


{11 \choose 1}  = 11


{11 \choose 2}  = \dfrac{11 \times 10}{2} = 55


{11 \choose 3}  = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165


(-3x+1)^{11} =  1 (-3x)^0 1^{11}  + 11(-3x)^{1} 1^{10}  + 55 (-3x)^2 1^{9}  + 165 (-3x)^3 1^8 + ...


(1-3x)^{11} =  1 -33 x + 495 3x^2 - 4455 x^3+ ...



6 0
3 years ago
WHAT IS THE NAME YOU OF A SOLID THAT HAS TWO PARRALLEL POLYGON BASES AND ALL OTHER FACES THAT ARE RECTANGLES 2 SEE ANSWERS
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5 0
3 years ago
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