Given end points of diameter,
(x1,y1)=(-3,-4)
(x2,y2)=(0,0)
Now,
the equation of circle is,
(x-x1)(x-x2)+(y-y1)(y-y2)=0
or, (x+3)(x-0)+(y+4)(y-0)=0
or, x^2 +3x +y^2 +4y =0
or, x^2 +y^2 +3x + 4y=0
which is in the form of x^2 +y^2 +2gx +2fy + c=0
where,
g=3/2
h=2
c=0
Now,
Answer:
Step-by-step explanation:
First, we can find the slope using the slope equation and two of the points.
Slope equation:
I'm going to use the first two points just so I can avoid the fraction... Substitute the x and y values into the equation.
Simplify:
Now that we have the slope, all we need is the y-intercept. Luckily, it gives it to us in the table. The x value of y-intercepts will always be 0. Looking at the table, we see that the point where x=0 is (0,2). Thus, the y-intercept is 2. Your final equation is