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3 years ago

Write an equation of the line passing through each of the following pairs of points. c (4, 0), (−2, 8)'

Mathematics

1 answer:

Tomtit [17]3 years ago

6 0

Answer:

Step-by-step explanation:

First, you must find the slope of the line using the formula (y2-y1/x2-x1). For your problem that would be (8-0/-2-4)= -4/3.

Then, you would plug in the slope and the y-intercept into the slope-intercept formula (y=mx+b), where m is the slope and b is the y intercept (4).

Your answer would be y=-4/3x+4

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The first drop down: (x-12),(x-80), (80-x), (12-x)

Mice21 [21]

Answer:x=12 and 68$

Step-by-step explanation:

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3 years ago

Quadrilateral ABCD is inscribed in a circle.

dem82 [27]

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

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3 years ago

5. h(x)=0.5x - 1 with domain (-♾, 4) what is the range

Rudiy27

We have a domain of a function, that is, which x-es can we throw in. But we are asking which y-s will we get given that we can only throw x-es in $(-\infty,4)$ .

Let's try $x=4$ even though we are forbidden to put 4 inside $h$ we are still able to do so.

So $h(4)=0.5\cdot4-1=2-1=1$ what we just got is the upper limit of the range. The lower limit is $h(-\infty)=-\infty$ .

So the range is just $(-\infty, 1)$ .

Hope this helps :)

6 0

3 years ago

Solve: the sum of two numbers is 70. one number is 4 times the other. what are the two numbers?

Thepotemich [5.8K]

Lets say two numbers are x and y

x+y=70-----------------------eq1

x=4y--------------------eq2

4y+y=70
5y=70
y=70/5
y=14

then x=4*14

x=56

8 0

3 years ago

In how many ways can 6 competitors finish a race assuming there are no ties?In how many ways can we sit n people on r < n cha

VLD [36.1K]

Answer: a) 720, b) $^nC_r=\dfrac{n!}{(n-r)!r!}$ c) 336, d) 30240 e) 120.

Step-by-step explanation:

Since we have given that

a) Number of competitors = 6

We need to find the number of ways that 6 competitors can finish a race and there are no ties.

So, Number of ways would be

$6!=720$

b) number of people = n

Number of chairs = r (r<n)

so, the number of ways we can sit n people on r<n chairs is given by

$^nC_r=\dfrac{n!}{(n-r)!r!}$

c) If there are three awards :

Gold, silver, bronze.

We need to find the number of ways that these medals can be awarded.

Number of ways is given by

$^8P_3\\\\=336$

d) Number of 5-digit zip codes are possible is given by

$^{10}P_5=30240$

e) Number of poeple = 10

Number of people required in committee = 3

Number of different 3 person committee that are selected from 10 people is given by

$^{10}C_3=120$

Hence, a) 720, b) $^nC_r=\dfrac{n!}{(n-r)!r!}$ c) 336, d) 30240 e) 120.

6 0

3 years ago