Question

Which equation represents a circle that contains the point (–5, –3) and has a center at (–2, 1)? distance formula: startroot (x 2 minus x 1) squared (y 2 minus y 1) squared endroot (x – 1)2 (y 2)2 = 25 (x 2)2 (y – 1)2 = 5 (x 2)2 (y – 1)2 = 25 (x – 1)2 (y 2)2 = 5

Answer 1

The equation of a circle that contains the point (–5, -3) and has a center at (-2, 1) is (x + 2)² + (y - 1)² = 25

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

The circle contains the point (–5, -3) and has a center at (-2, 1), hence:

$radius=\sqrt{(1-(-3))^2+(-2-(-5))^2}=5\ units$

The equation is:

(x - (-2))² + (y - 1)² = 5²

(x + 2)² + (y - 1)² = 25

The equation of a circle that contains the point (–5, -3) and has a center at (-2, 1) is (x + 2)² + (y - 1)² = 25

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