I'm a bit lost on this question maybe someone can help me out
2 answers:
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Answer:
OD) 4.9 units, 14.2 units
<em> The lengths of the legs of a right triangle</em>
<em> </em>a = 4.9units , b = 14.2units and hypotenuse 'c' = 15
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the Acute angle is 19°
And hypotenuse (AC ) = c= 15
We will take cos∝ =
⇒
⇒ BC = 15 × cos 19°
⇒ BC = 15 ×0.9455
⇒ BC = 14.18
The length of the one leg of the right angle triangle
BC = b = 14.18≅ 14.2
We know that ΔABC is a right angle triangle
a² = c² - b²
= 15² - (14.18)²
= 225 - 201.07
= 23.93
a² = 23.93
a = √23.93 = 4.89≅4.9
<u><em>Final answer:-</em></u>
<em> The lengths of the legs of a right triangle</em>
<em> </em>a = 4.9units , b = 14.2units and hypotenuse 'c' = 15
Using the z-distribution, it is found that the 95% confidence interval for the proportion of all U.S. adults who play video games is (0.4681, 0.5119). It means that we are 95% sure that the true proportion of all U.S. adults who play video games is between 0.4681 and 0.5119.
<h3>What is a confidence interval of proportions?</h3>A confidence interval of proportions is given by:
In which:
is the sample proportion.
- z is the critical value.
- n is the sample size.
In this problem, we have that:
- 95% confidence level, hence
, z is the value of Z that has a p-value of
, so
.
- 49% out of 2001 U.S. adults play video games, hence
.
The lower bound of the interval is:
The upper bound of the interval is:
The 95% confidence interval for the proportion of all U.S. adults who play video games is (0.4681, 0.5119). It means that we are 95% sure that the true proportion of all U.S. adults who play video games is between 0.4681 and 0.5119.
To learn more about the z-distribution, you can take a look at brainly.com/question/25730047