3. What is the best description of an isosceles triangle?

Need these for geometry, please help asap!

Vlad [161]

Answer:

This is simple. The answer is 60 for the first, and the second one I believe is 85

Step-by-step explanation:

Since we are dealing with quadrilaterals, we know that all the inside angles add up to 360. In your isosceles trap. the top two angles are the same, and the bottom two are the same. So, we can do 120*2=240 for the top angles, and then subtract that from 360. 360-240=120. 120/2=60

Hope it helps

5 0

3 years ago

Tossing a coin and spinning a spinner with five equal sections, 1-5

LUCKY_DIMON [66]

Answer:

Its gonna be a 50/50 on the coin and 20/100 chance for the spinner

5 0

3 years ago

Read 2 more answers

D(n) = 6 - 4(n - 1) encuentra el 5° término se la sucesión

Rudiy27

Ouuu ion I gotta do the math on it cause I’m not on math rn

6 0

3 years ago

If XX is a binomial random variable, compute the mean, the standard deviation, and the variance for each of the following cases:

Liula [17]

Answer:

(a) The mean, variance and standard deviation of X are 1.60, 0.96 and 0.98 respectively.

(b) The mean, variance and standard deviation of X are 3.20, 0.64 and 0.80 respectively.

(c) The mean, variance and standard deviation of X are 1.50, 0.75 and 0.87 respectively.

(d) The mean, variance and standard deviation of X are 4.00, 0.80 and 0.89 respectively.

Step-by-step explanation:

The random variable X follows a Binomial distribution with parameters n and p.

The mean, variance and standard deviation of X are:

$\mu=np\\\sigma^{2}=np(1-p)\\\sigma=\sqrt{np(1-p)}$

(a)

For n = 4 and p = 0.40 compute the mean, variance and standard deviation of X as follows:

$\mu=np=4\times0.40=1.60\\\sigma^{2}=np(1-p)=4\times0.40\times(1-0.40)=0.96\\\sigma=\sqrt{np(1-p)}=\sqrt{0.96}=0.98$

Thus, the mean, variance and standard deviation of X are 1.60, 0.96 and 0.98 respectively.

(b)

For n = 4 and p = 0.80 compute the mean, variance and standard deviation of X as follows:

$\mu=np=4\times0.80=3.20\\\sigma^{2}=np(1-p)=4\times0.80\times(1-0.80)=0.64\\\sigma=\sqrt{np(1-p)}=\sqrt{0.64}=0.80$

Thus, the mean, variance and standard deviation of X are 3.20, 0.64 and 0.80 respectively.

(c)

For n = 3 and p = 0.50 compute the mean, variance and standard deviation of X as follows:

$\mu=np=3\times0.50=1.50\\\sigma^{2}=np(1-p)=3\times0.50\times(1-0.50)=0.75\\\sigma=\sqrt{np(1-p)}=\sqrt{0.75}=0.87$

Thus, the mean, variance and standard deviation of X are 1.50, 0.75 and 0.87 respectively.

(d)

For n = 5 and p = 0.80 compute the mean, variance and standard deviation of X as follows:

$\mu=np=5\times0.80=4.00\\\sigma^{2}=np(1-p)=5\times0.80\times(1-0.80)=0.80\\\sigma=\sqrt{np(1-p)}=\sqrt{0.80}=0.89$

Thus, the mean, variance and standard deviation of X are 4.00, 0.80 and 0.89 respectively.

6 0

3 years ago

Flies in a nest double every 12 hours. If the nest starts with 10 flies, how many will you have in 3 days?

irinina [24]

You would have 640 flies in 3 days.

5 0

3 years ago