$\text{Hey there!}\\\text{What number ten more than 985?}\\\\\text{In order for you to find the number that's 10 more than 985. you can}\\\text{add 10 plus the number 985}\\\\\text{So, 985 + 10 = ? }\\\\\text{? = the mystery number}\\\\\text 10 + 985 = 995}\\\\\boxed{\boxed{\text{Answer: 995}}}\checkmark$

$\text{We added because you put the word MORE in the sentence}\\\text{And more can mean GO UPWARD}$

$\text{If you were to say less than you would have to subtract. Since,}\\\text{you are going downward }$

$\text{Good luck on your assignment and enjoy your day!}\\\\\frak{LoveYourselfFirst:)}$

6 0

3 years ago

A tank contains 30 lb of salt dissolved in 300 gallons of water. a brine solution is pumped into the tank at a rate of 3 gal/min

sesenic [268]

$A'(t)=(\text{flow rate in})(\text{inflow concentration})-(\text{flow rate out})(\text{outflow concentration})$
$\implies A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\left(2+\sin\dfrac t4\right)\dfrac{\text{lb}}{\text{gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}$
$A'(t)+\dfrac1{100}A(t)=6+3\sin\dfrac t4$

We're given that $A(0)=30$ . Multiply both sides by the integrating factor $e^{t/100}$ , then

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$\left(e^{t/100}A(t)\right)'=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$e^{t/100}A(t)=600e^{t/100}-\dfrac{150}{313}e^{t/100}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+C$
$A(t)=600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+Ce^{-t/100}$

Given that $A(0)=30$ , we have

$30=600-\dfrac{150}{313}\cdot25+C\implies C=-\dfrac{174660}{313}\approx-558.02$

so the amount of salt in the tank at time $t$ is

$A(t)\approx600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)-558.02e^{-t/100}$

3 0

3 years ago

Match the equation with property used

nata0808 [166]

I dont really know the difference between them lol; also it's a little blurry

sorry

7 0

2 years ago