The area of your figure is the sum of the areas of the base cuboid and the lateral area of the "tower."
The top and bottom areas of the base cuboid are (10 in)*(10 in) = 100 in^2, for a total of 2*100 in^2 = 200 in^2.
The lateral area of the base cuboid is its perimeter (4*10 in = 40 in) multiplied by its height (2 in), so is 80 in^2.
Likewise, the lateral area of the "tower" is the product of its perimeter (4*5 in = 20 in) and its height (8 in), so is 160 in^2.
The sum of all these is 200 in^2 +80 in^2 +160 in^2 = 440 in^2.
The 3rd selection is appropriate.
In 500 seconds, there are 8.33 minutes. However with that knowledge, 500 seconds is greater.
The answer is 2285.92 in³.
STEP 1: Calculate the volume of the log: V1 = ?
STEP 2: Calculate the volume of the cylinder: V2 = ?
STEP 3: Subtract these two volumes to get <span> the volume of the remaining portion of the log: V = V1 - V2
The volume of a cylinder is:
V = </span>π · r² · h
(π = 3.14, r - radius, h - height)
It is given:
h1 = h2 = h = 28 in (height of the log is the same as the height of the cylinder)
r1 = 7.5 in
r2 = 5.5 in
STEP 1: Calculate the volume of the log: V1 = ?
V1 = π · r1² · h = 3.14 · 7.5² · 28 = 4945.5 in³
STEP 2: Calculate the volume of the cylinder: V2 = ?
V2 = π · r2² · h = 3.14 · 5.5² · 28 = 2659.58 in³
STEP 3: Subtract these two volumes to get the volume of the remaining portion of the log:
V = V1 - V2 = 4945.5 in³ - 2659.58 in³ = 2285.92 in³
The value of
can be calculated using the logarithm rule.
The value of
is 3.
Given:
The given expression is,
![\log_5125](https://tex.z-dn.net/?f=%5Clog_5125)
<h3>What is a logarithm?</h3>
The logarithm is the inverse function of exponentiation. In logarithm base must be raised to yield a given number for an exponent.
Calculate the value of given logarithm.
![\log_5125=\log_5(5)^3\\ \log_5125=3\log_55](https://tex.z-dn.net/?f=%5Clog_5125%3D%5Clog_5%285%29%5E3%5C%5C%0A%5Clog_5125%3D3%5Clog_55)
From logarithm rule ![\log m^n=n \log m](https://tex.z-dn.net/?f=%5Clog%20m%5En%3Dn%20%5Clog%20m)
![\log_5125=3\times 1\\ \log_5125=3](https://tex.z-dn.net/?f=%5Clog_5125%3D3%5Ctimes%201%5C%5C%0A%5Clog_5125%3D3)
Thus, the value of
is ![3](https://tex.z-dn.net/?f=3)
Learn more about the logarithm rule here:
brainly.com/question/7302008
Y= 24 now 3x is just 3 maybe I think cause x is a improper value