WILL AWARD BRAINLIEST!
1 answer:
Answer: 27465 km/h
Step-by-step explanation:
From the figure, let us use cosine formula to calculate the resultant displacement.
B^2 = C^2 + A^2 - 2(A)(C) cosØ
Where C = 580km
A = 360 km
Ø = 153 degree
Substitute all the parameters into the formula
B^2 = 580^2 + 360^2 - 2(360)(580)cos153
B^2 = 466000 - ( - 372084.32 )
B^2 = 466000 + 372084.32
B^2 = 838084.32
Square root both sides
B = 915.5 km
You are told to use a scale of 1 cm to 50 km.
Therefore, B = 915.5/50 = 18.3 cm
The time given are: 09:23 and 09:25.
The time difference = 25 - 23 = 2 minute.
Convert minutes to hours
2 minute = 2/60 = 1/30 hours
Speed = distance/time
Speed = 915.5 ÷ 1/30
Speed = 915.5 × 30
Speed = 27465 km/h
Or
Convert 2 minute to second
2 minute = 2 × 60 = 120 seconds
Speed = distance/time
Speed = 18.3/120
Speed = 0. 1525 cm/s
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<span> If the lines are the same, the equations are dependent linear equations. Using the graph of y = x and x + 2y = 6, shown below, determine how many solutions the system has. Then classify the system as consistent or inconsistent and the equations as dependent or independent. The lines intersect at one point.</span>
Hope This Helps!
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<span> If the lines are the same, the equations are dependent linear equations. Using the graph of y = x and x + 2y = 6, shown below, determine how many solutions the system has. Then classify the system as consistent or inconsistent and the equations as dependent or independent. The lines intersect at one point.</span>
Hope This Helps!
:D
Answer:
a. A) Yes; as sample size increases, effect size increases.
b. A) The critical value increases.
Step-by-step explanation:
a.
If all possible samples of size N are drawn from a finite population, Np, without replacement, and the standard deviation of the mean values of the sampling distribution of means is determined then:
σx =d √N
d = σx . √N
d ∞ N
from this, we can say d is directly proportional to √N
where σx is the standard deviation of the sampling distribution of means and d is the standard deviation of the population’. The standard deviation of a sampling distribution of mean values is called the standard error of the means,
therefore, we can conclude that:
A) Yes; as sample size increases, effect size increases.
b.
In this estimate, tc is called the confidence coefficient for small samples, d is the standard deviation of the sample, x is the mean value of the sample and N is the number of members in the sample.
When determining the t-value, given by
t =(
(x−µ) /s) *
it is necessary to know the sample parameters x and s and the population parameter µ. x and s can be calculated for the sample, but usually an estimate has to be made of the population mean µ, based on the sample mean value.
from the above equation it can be deduced that t value is determined with the sample size, and as the sample size increases
A) The critical value increases.