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Ivahew [28]
2 years ago
7

How far below the bridge will kate eventually be hanging, once she stops oscillating and comes finally to rest? assume that she

doesn't touch the water
SAT
1 answer:
shepuryov [24]2 years ago
6 0

The distance below the bridge that  kate will eventually be hanging, once she stops oscillating and comes finally to rest is: d = mg/k + L.

<h3>Distance</h3>

LetForce exerted by a spring=F=kx

Let x = (d – L)

Let d= Total length of the bungee cord

Let set this equal to the gravitational force

F(spring) = k(d – L)

F(gravity) = mg

Hence:

k(d – L) = mg

(d – L) = mg/k

d = mg/k + L

Inconclusion  the distance below the bridge that  kate will eventually be hanging, once she stops oscillating and comes finally to rest is: d = mg/k + L.

Learn more about distance here:brainly.com/question/15159264

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