Friction is the resistance to motion of one object moving relative to another. It is not a fundamental force, like gravity or electromagnetism. Instead, scientists believe it is the result of the electromagnetic attraction between charged particles in two touching surfaces.
The period, phase shift, and vertical shift are; Period is 2π/3, Shift is 4 units to the left and vertical shift is 6 units up.
<h3>How to find waveform properties?</h3>
We are given the waveform equation as;
csc[3(x + 4)] + 6.
Expanding this gives us;
csc[3x + 12] + 6.
Period = 2π/b
From the given waveform, b = 3. Thus;
Period = 2π/3
Phase shift = -c/b
where c from the given waveform is 12. Thus;
Phase shift = -12/3 = -4
Thus, phase shift is 4 units to the left while vertical shift is 6 units upawrds.
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Answer:
54 degrees
Explanation:
Plot point X on the left of point A on line l. Lines l and m are parallel, and segment AB is the transversal. Angles BAX and ABC are alternate interior angles, so they are congruent (same angle measures). Since segment BD bisects angle ABC, angles ABD and DBC are congruent. Therefore angle ABD is 108/2 = 54 degrees. In the diagram, we can also see that angle DAB is 180-108 = 72 degrees. Since interior angles of a triangle add up to 180, angle ADB is 180-72-54 = 54 degrees.
Answer: evaluate
Explanation:
Trailing the Text is a technique useful to analyze how a notable event is depicted in a text, meaning how it´s introduced, elaborated, and illustrated.
The introduction refers to the presentation of the event. The elaboration provides further details about it, and the illustration refers to the pictures that represent it.
The combined area of the shaded triangles in Figure 1 is equal to the combined area of the shaded triangles in Figure 2. The area of the unshaded square in Figure 1 can be represented by . The combined area of the two unshaded squares in Figure 2 can be represented by . The areas of the squares in Figure 1 and Figure 2 show that .
Given :
Figure 1 and figure 2 are given.
The combined area of the shaded triangles in Figure 1 is equal to the combined area of the shaded triangles in Figure 2.
The area of the unshaded square in Figure 1 can be represented by .
The combined area of the two unshaded squares in Figure 2 can be represented by .
The areas of the squares in Figure 1 and Figure 2 show that .