Geometry help please

A bucket contains five green tennis balls, two yellow tennis balls, six red tennis balls, and eight blue tennis balls. Tony remo

vichka [17]

Answer:

The probability that Tony removes one yellow, one green ,one blue,and then one more blue tennis ball is 0.0039.

Step-by-step explanation:

We are given that a bucket contains five green tennis balls, two yellow tennis balls, six red tennis balls, and eight blue tennis balls.

As we know that, <u>Probability of an event</u> = $\frac{\text{Favorable number of outcomes}}{\text{Total number of outcomes}}$

Number of green tennis balls = 5

Number of yellow tennis balls = 2

Number of red tennis balls = 6

Number of blue tennis balls = 8

Total number of tennis balls = 5 + 2 + 6 + 8 = 21

{Now it should be notes that Tony removes for tennis balls, without replacement from the bucket means that every time the total number of remaining balls available for selecting will be one less}.

Now, Probability that Tony removes one yellow = $\frac{2}{21}$

Probability that Tony removes one green = $\frac{5}{20}$

Probability that Tony removes one blue = $\frac{8}{19}$

Probability that Tony removes one blue again = $\frac{7}{18}$

SO, final probability is = $\frac{2}{21} \times \frac{5}{20} \times \frac{8}{19} \times \frac{7}{18}$

= $\frac{2}{513}$

= <u>0.0039</u>

3 0

3 years ago

Can someone please help me ASAP❤️

Eddi Din [679]

38,320 (for positive scientific notation you move the decimal to the right how ever many places, so move the decimal 4 places to the right in this case)

4 0

3 years ago

A student finishes the first half of an exam in the time it takes him to finish the second half. If the entire exam takes him an

strojnjashka [21]

Part 1 took 30 minutes and part 2 took 30 minutes

8 0

3 years ago

11z 5 = 9z + 7 how do u solve this?

lorasvet [3.4K]

Answer:Z=1

Step-by-step explanation: if it is 11z+5, then... minus 9z on each side to get 2z+5=7. Minus 5 on each side to get 2z=2. Divide bboth sides by two to get 1z=1.

6 0

2 years ago

What is the solution to this system of equations?

Ede4ka [16]

Answer:

First choice.

Step-by-step explanation:

You could plug in the choices to see which would make all the 3 equations true.

Let's start with (x=2,y=-6,z=1):

2x+y-z=-3

2(2)+-6-1=-3

4-6-1=-3

-2-1=-3

-3=-3 is true so the first choice satisfies the first equation.

5x-2y+2z=24

5(2)-2(-6)+2(1)=24

10+12+2=24

24=24 is true so the first choice satisfies the second equation.

3x-z=5

3(2)-1=5

6-1=5

5=5 is true so the first choice satisfies the third equation.

We don't have to go any further since we found the solution.

---------Another way.

Multiply the first equation by 2 and add equation 1 and equation 2 together.

2(2x+y-z=-3)

4x+2y-2z=-6 is the first equation multiplied by 2.

5x-2y+2z=24

----------------------Add the equations together:

9x+0+0=18

9x=18

Divide both sides by 9:

x=18/9

x=2

Using the third equation along with x=2 we can find z.

3x-z=5 with x=2:

3(2)-z=5

6-z=5

Add z on both sides:

6=5+z

Subtract 5 on both sides:

1=z

Now using the first equation along with 2x+y-z=-3 with x=2 and z=1:

2(2)+y-1=-3

4+y-1=-3

3+y=-3

Subtract 3 on both sides:

y=-6

So the solution is (x=2,y=-6,z=1).

8 0

3 years ago