Answer:
3
Step-by-step explanation:
1+2x=7
7-1=6
2x=6
6/2=3
x=3
Answer:
Step-by-step explanation:
Equation given
tan(3B-32 ) = cot ( 5B +10 ) = tan [ 90 - ( 5B + 10 ) ]
tan(3B-32 ) = tan (90 - 5B - 10 )
(3B-32 ) = (90 - 5B - 10 )
8B = 32 + 80
B = 14° .
So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
brainly.com/question/11377865
#SPJ4
Answer:
c
Step-by-step explanation:
Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:
(-15,-10).
<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>
It is given by the derivative at x = x0, that is:
.
In this problem, the function is:

Hence the derivative is:

For a slope of -1, we have that:
0.4x + 5 = -1
0.4x = -6
x = -15.
For a slope of 1, we have that:
0.4x + 5 = 1.
0.4x = -4
x = -10
Hence the interval is:
(-15,-10).
More can be learned about derivatives and tangent lines at brainly.com/question/8174665
#SPJ1