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Paul [167]
3 years ago
7

Find x. A) 3 B) 3.75 C) 4.25 D) 5

Mathematics
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer: B

Step-by-step explanation:

By the intersecting chords theorem, (3)(5)=4x, meaning x=3.75.

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Please help me with my math question!!!
Ierofanga [76]

Answer:

2x^9(6x^3+x^2-4x+5x^-9)

Step-by-step explanation:

2x^9(6x^3+x^2-4x+5x^-9)

6 0
4 years ago
Suppose you graph y=5x and y=x+500 on the same coordinate plane.Which line would be steeper?Why?
solong [7]
Slope tells the steepness of the graph
y=mx+b
m=slope
so if m is bigger,t hen sloe is bigger
y=5x+0
slope is 5
y=1x+500
slope is 1

y=5x is steeper
8 0
3 years ago
Read 2 more answers
If P*Q = PxQ - 7,<br> what is 9*5?
ycow [4]

Given problem:

 What is 9*5;

 The formula P*Q  = P x Q  - 7;

To  find 9*5, simply make P = 9 and Q = 5

Input into the equation and solve;

   

   P*Q  = P x Q  - 7    =   9 x 5 - 7

                                 = 45 - 7

                                 = 38

The solution to this problem is 38.

4 0
3 years ago
Two rectangles have the same area. One says x + 3 and x + 1 and the other says x + 6 and x. What is the value of x?
Taya2010 [7]
(x+3)(x+1)=(x+6)(x)
x^2+x+3x+3=x^2+6x
x^2+4x+3=x^2+6x
4x+3=6x
3=2x
x=1.5

Hope this helps :)
4 0
3 years ago
An agronomist hopes that a new fertilizer she has developed will enable grape growers to increase the yield of each grapevine by
Phoenix [80]

Answer:

Yes. Fertilization increases grape yields by more than 5 pounds.

Step-by-step explanation:

Let f-fertilized and o-old(unfertilized)

#First, we use our data to calculate the standard error:

SE(\bar y_f-\bar y_o)=\sqrt{\frac{s_f^2}{n_f}+\frac{s_o^2}{n_o}}\\\\=\sqrt{\frac{3.7^2}{44}+\frac{3.4^2}{47}}\\\\=0.7464

#State both null and alternative hypothesis:

H_o:\mu_f-\mu_o=0\\\\H_A=\mu_f-\mu_o>0

#We determine our degrees of freedom as 87.02(using R), we now compute the t-value as:

t=\frac{\bar y_f-\bar y_o}{\sqrt{\frac{s_f^2}{n_f}+\frac{s_o^2}{n_o}}}\\\\\\t=\frac{53.4-52.1}{\sqrt{\frac{s_f^2}{n_f}+\frac{s_o^2}{n_o}}}\\\\\\t=\frac{1.3}{0.7464}\\\\t=1.7417\\\\P=P(t_{87.0>1.7417}=1-0.9575=0.0.0425

Since, the p-value is low, we Reject the null hypothesis. The is enough evidence suggesting that grape yields increase by more than 5 pounds than mean yields of  unfertilized grapes.

8 0
4 years ago
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