2/5 + 1/9
18/45 + 5/45 = 23/45
B.23/45 is your answer
hope this helps
<span>Four friends were born on consecutive years.
The sum of their ages is 62. Let's find the age of the youngest friend:
</span><span>Formula:
4x + 6 = 62
=> First is to Subtract 6 from both sides
4x = 56
Then next thing to do is to divide 4 from both sides:
=> x = 14
14 + 14 + 1 + 14 + 2 + 14 + 3 = 62
62 = 62
Thus the youngest age is 14</span>
Answer:
each child get 4
Step-by-step explanation:
