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77julia77 [94]
3 years ago
10

Which represents the solution(s) of the graphed system of equations, y = x2 x – 2 and y = 2x – 2? (–2, 0) and (0, 1) (0, –2) and

(1, 0) (–2, 0) and (1, 0) (0, –2) and (0, 1)
Mathematics
1 answer:
Marysya12 [62]3 years ago
7 0

The solution to the system of equation are (0, -2) and (1, 0)

<h3>Solution to system of equations</h3>

System of equations are equations that has unknown and more than 1 equations.

Given the system of equations

y = x^2 + x – 2

y = 2x – 2

Equate both expressions

x^2 + x -2 = 2x - 2
x^2 - x = 0
x(x-1) = 0
x = 0 and x - 1 = 0
x = 0 and 1

If x = 0

y = 0 - 2 = -2

If x = 1

y = 2 - 2 = 0
Hence the solution to the system of equation are (0, -2) and (1, 0)

Learn more on system of equation here: brainly.com/question/13729904

#SPJ4

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1. A weighted coin is biased so that a head is twice as likely to occur as a tail. If the coin is tossed 4 times, what is the pr
ohaa [14]

Answer:

80/81

Step-by-step explanation:

If a head is twice as likely to occur as a tail, then the probability of getting heads is 2/3 and the probability of getting tails is 1/3.

The probability of getting at least 1 head involves 4 scenarios:

1) 1 Head and 3 Tails

2) 2 Heads and 2 Tails

3) 3 Heads and 1 Tail

4) 4 Heads

Instead of calculate all these scenarios, you could calculate the opposite scenario: 4 Tails. The sum of all possible scenarios is 1, so:

P(at least one head) + P(no heads) = 1

Then, P(at least one head) = 1 - P(no heads)

The probability of 4 tails is:

P(no heads) = P(TTTT) = (1/3)(1/3)(1/3)(1/3)=1/81

Then, P(at least one head) = 1 - 1/81=80/81

7 0
3 years ago
What is the equation of a line with a slope of -2 that passes through the point (-2,12)?
slavikrds [6]

Answer:

y=-2x + 8 which is the required equation

Which is option C

Step-by-step explanation:

Given:

Slope = m = -2

Given points are ( -2,12)

Which is

x = -2 and y =12

TO find:

Equation of line passing through these points = ?

Solution:

The point slope form of a line is

y = mx + c

Here we don't know the value of c

To find it

Putting y = 12 , x= -2 and y = -2 in the given equation

y = mx + c

Putting values it becomes

12 = (-2)*(-2) + c

12 = 4 + c

Subtracting 4 from both sides

12-4 = 4 -4 + c

8 = c

Now we have

m = -2 and c= 8

So equation of a line is given by

y = mx + c

Putting value of m and c

y = -2*x + 8

y=-2x + 8 which is the required equation


7 0
3 years ago
Read 2 more answers
What is the quotient?
Setler79 [48]

Answer:

Option 3) \frac{1}{(t+4)^{2}}

Step-by-step explanation:

In the given question we have to calculate the quotient after division.

To solve this question we will factorize (t²+7t+12) first and then we will will divide by this.

⇒ t²+7t+12 = ( t²+4t+3t+12)

⇒ t(t+4)+3(t+4)

⇒ (t+3)(t+4)

Now its a simpler form of divisor to get the answer.

We come back to the question

\frac{(t+3)}{t+4}\div(t^{2}+7t+12)

= \frac{(t+3)}{t+4}\div(t+3)(t+4)

Or =\frac{(t+3)}{t+4}\times\frac{1}{(t+3)(t+4)}

=\frac{1}{(t+4)^{2}}

So the right answer is \frac{1}{(t+4)^{2}}

5 0
3 years ago
If f(x) = x + 2 and g(x) = 3x +4, then (g °f)(x) = ?
Anastaziya [24]

The correct answer is a. 3x + 6

In order to find a compound function, you must use the first letter in the function (in this case f) and plug the second letter (g) in where you see x's.

f(x) = x + 2

f(g(x)) = (g(x)) + 2

f(g(x)) = (3x + 4) + 2

f(g(x)) = 3x + 6

7 0
4 years ago
Can someone help me for question 18 pls? I really need help to solve this question!!
earnstyle [38]

Plug the x-values from the table into the given equation and solve for y.

y = 5 - x²

<u>First column</u>

replace x with -2

y = 5 - (-2)²

  = 5 - (4)

  = 1

(x, y) = (-2, 1)

<u>Second column</u>

replace x with -1

y = 5 - (-1)²

  = 5 - (1)

  = 4

(x, y) = (-1, 4)

<u>Third column</u>

replace x with 0

y = 5 - (0)²

  = 5 - (0)

  = 5

(x, y) = (0, 5)

<u>Fourth column</u>

replace x with 1

y = 5 - (1)²

  = 5 - (1)

  = 4

(x, y) = (1, 4)

<u>Fifth column</u>

replace x with 2

y = 5 - (2)²

  = 5 - (4)

  = 1

(x, y) = (2, 1)

3 0
4 years ago
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