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Tresset [83]
3 years ago
15

9 points

Mathematics
2 answers:
andrezito [222]3 years ago
8 0

Answer:

$40-$50

Step-by-step explanation:

Assuming Miguel makes $200 every paycheck and is charged $10 each time, then we just need to multiply $10 by the number of paychecks he cashes each month. He's charged $10 four times a month. 10x4=40. So Miguel is charged $40 a month to cash his paychecks.

Vanyuwa [196]3 years ago
3 0

the answer is $40-$50

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The side of each of the equilateral triangles in the figure is twice the side of the central regular hexagon. What fraction of t
lana [24]

Answer:

The fraction is 1/4

Step-by-step explanation:

we know that

The area of an equilateral triangle, using the law of sines is equal to

A=\frac{1}{2}x^{2}sin(60^o)

A=\frac{1}{2}x^{2}(\frac{\sqrt{3}}{2})

A=x^{2}\frac{\sqrt{3}}{4}

where

x is the length side of the triangle

In this problem

Let

b ----> the length side of the regular hexagon

2b ---> the length side of the equilateral triangle

step 1

Find the area of the six triangles

Multiply the area of one triangle by 6

A=6[x^{2}\frac{\sqrt{3}}{4}]

A=3x^{2}\frac{\sqrt{3}}{2}

we have

x=2b\ units

substitute

A=3(2b)^{2}\frac{\sqrt{3}}{2}\\\\A=6b^{2}\sqrt{3}\ units^2

step 2

Find the area of the regular hexagon

Remember that, a regular hexagon can be divided into 6 equilateral triangles

so

The area of the regular hexagon is the same that the area of 6 equilateral triangles

A=3x^{2}\frac{\sqrt{3}}{2}

we have

x=b\ in

substitute

A=3(b)^{2}\frac{\sqrt{3}}{2}

step 3

To find out what fraction of the total area of the six triangles is the area of the hexagon, divide the area of the hexagon by the total area of the six triangles

3(b)^{2}\frac{\sqrt{3}}{2}:6b^{2}\sqrt{3}=\frac{3}{2} :6=\frac{3}{12}=\frac{1}{4}

3 0
3 years ago
How many vertices are in a polyhedron with 6 triangular faces?
Bingel [31]
I believe it will be 36 Im sorry if im wrong.
6 0
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2)\ \ \ 6.94\%\ daily\\\\ \ \Rightarrow\ \  \frac{1}{365} \cdot6.94\% \approx0.019\%\ \ annually\ \ \Rightarrow\ \ p=0.019\\\\ daily\ \Rightarrow\  365\ times\ annually\ \Rightarrow\ 1420\ times\ in\ 4\ years\ \Rightarrow\ n=1420\\\\Sum(6.94\%)=\$10,000\cdot(1+ \frac{0.019}{100})^{1420}=\\ \\.\ \ \ \ \ \ \ \ \ \ \ \ =\$10,000\cdot(1+0,00019)^{1420}\approx\$13096.69\\---------------------------\\\$13,199.29 > \$13,096.69\\\\Ans.\ the\ larger\ amount\ gives\ the\ compounded\ quarterly.
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Answer:

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Brilliant_brown [7]

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