Answer: 5.37
Step-by-step explanation:
Let x = ACT scores.
Given: ACT scores have a mean of 20.8 and 9 percent of the scores are above 28. The scores have a distribution that is approximately normal.
i.e. P(X>28)=0.09 (i)
Now,
![P(X>28)=P(\dfrac{X-\mu}{\sigma}>\dfrac{28-20.8}{\sigma})\\\\= P(z>\dfrac{7.2}{\sigma})\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]](https://tex.z-dn.net/?f=P%28X%3E28%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B28-20.8%7D%7B%5Csigma%7D%29%5C%5C%5C%5C%3D%20P%28z%3E%5Cdfrac%7B7.2%7D%7B%5Csigma%7D%29%5C%20%5C%20%5C%20%5C%20%5Bz%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D)
(ii)
One -tailed z value for p-value of 0.09 =1.3408 [By z-table]
From (i) and (ii)
Hence, the standard deviation = 5.37
9514 1404 393
Answer:
- 85°
- 60°
Step-by-step explanation:
1. Angle JKL is half the measure of the intercepted arc JK.
(1/2)JK = 1/2(360° -190°) = (1/2)(170°) = 85°
angle JKL is 85°
__
2. The angle between tangents is the supplement of the intercepted arc.
angle JKL = 180° -(360° -240°)
angle JKL = 60°
Answer:
wait do you still need the answer?
Use division or long division (ignore the decimal point)
Then put the decimal in the same spot as the dividend (the number being divided)
You may have have forgotten to find the measure of A. Which would by using your 6 that you got would be 19.
16X-6=90
96=16X
X=6
8X6-29
48-29
19
