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olasank [31]
4 years ago
14

Given a spherical weather balloon with a volume of 36π cubic feet. What is the diameter, in feet, of the weather balloon?

Mathematics
2 answers:
Vlad [161]4 years ago
8 0

Answer:

option B D=6\ ft

Step-by-step explanation:

we know that

The volume of the sphere is equal to

V=\frac{4}{3}\pi r^{3}

In this problem we have

V=36\pi\ ft^{3}

substitute and solve for r

36\pi=\frac{4}{3}\pi r^{3}

simplify

27=r^{3}

r=3\ ft

Find the diameter

D=2r=2(3)=6\ ft

Mashutka [201]4 years ago
6 0

Answer:

b)6

Step-by-step explanation:

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The radius of the planet Uranus is approximately 4 times the size of the radius of Earth. What does this tell you about the volu
Sonja [21]

Answer:

Step-by-step explanation:

Earth volume is approximately V = (4/3)πr³, and

Uranus volume is approximately V = (4/3)π(4r)³, or (4/3)π*64*r³

Comparing these two results, we see that the volume of Uranus is approximately 64 times greater than the volyume of Earth.

5 0
3 years ago
Read 2 more answers
The distance between the parallel lines x – 2y = 3 and 2x – 4y = 12 is
Svetradugi [14.3K]

Given :

Parallel lines are

x – 2y = 3 and 2x – 4y = 12

Step-by-step explanation:

Lets write the given lines in slope intercept form y=mx+b

x -2y = 3  \\-2y=-x+3\\Divide \; both \; sides \; by -2\\y=\frac{x}{2} -\frac{3}{2}

From the above equation , y intercept of first line is \frac{-3}{2}

Solve the second equation for y and find out y intercept

2x-4y=12\\-4y=-2x+12\\Divide \; by \; -4\\y=\frac{1}{2} x-3

y intercept of second line is -3

To find the distance between parallel lines, we subtract the y intercepts

\frac{-3}{2} -(-3)=\frac{-3}{2} +\frac{6}{2} =\frac{3}{2} =1.5

Answer:

The distance between the parallel lines = 1.5

Reference:

brainly.com/question/24145911

7 0
3 years ago
Read 2 more answers
If f(x)=2x-6 and g(x)=x^3 what is (g f)(0)
kow [346]
<h2>Hello!</h2>

The answer is:

(g\circ f)(0)=-216

<h2>Why?</h2>

To composite functions, we need to evaluate functions in another function(s), for example:

Given f(x) and g(x), if we want to calculate f(x) composite g(x), we need to evaluate g(x) into f(x).

So, we are given the functions:

f(x)=2x-6\\g(x)=x^{3}

And we are asked to calculate g(x) composite f(x), and then evaluate "x" to 0, so, calculating we have:

(g\circ f)(x)=g(f(x))\\\\(g\circ f)(x)=(2x-6)^{3}

Now that we have the composite function, we need to evaluate "x" equal to 0, so:

(g\circ f)(0)=(2x-6)^{3}\\\\(g\circ f)(0)=(2*(0)-6)^{3}=(0-6)^{3}=-6*-6*-6=-216

Hence, we have that:

(g\circ f)(0)=-216

Have a nice day!

6 0
4 years ago
Let f(x) = x^2 + 4x - 31. for what value of a is there exactly one real value of x such that f(x) = a?
allsm [11]
This value of "a" is exactly the y-coordinate of the vertex of the parabola
y = x%5E2+%2B+4x++-+31.

To find it, complete the square:

x%5E2+%2B+4x++-+31 = %28x%2B2%29%5E2+-+4+-+31 = %28x%2B2%29%5E2+-+35.

So, this value of "a" is a = -35.










Figure. Plot y = x%5E2+%2B+4x++-+31.


5 0
3 years ago
A jewelry stand sells 5 different pairs of earrings. The earrings sell for $12, $9, $6, $8, and $10.
Maslowich
The answer is $1.6

Step 1. Find the mean of all values (X = ?).
Step 2. Find the distance of all values from the mean (d1, d2, d3, d4, d5).
Step 3. Find the mean of distances (D).

x1 = $12
x2 = $9
x3 = $6
X4 = $8
x5 = $10

Step 1.
X = (x1 + x2 + x3 + x4 + x5)/5
    = (12 + 9 + 6 + 8 + 10)/5
    = 45/5
    = $9

Step 2.
d1 = 12 - 9 = 3
d2 = 9 - 9 = 0
d3 = 9 - 6 = 3
d4 = 9 - 8 = 1
d5 = 10 - 9 = 1

Step 3.
D = (d1 + d2 + d3 + d4 + d5)/5
    = (3 + 0 + 3 + 1 + 1)/5
    = 8/5
    = $1.6
3 0
3 years ago
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