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3 years ago

PLEASE HELP ASAP! I WILL GIVE BRAINLIEST!

Mathematics

2 answers:

olga_2 [115]3 years ago

6 0

In 75 minutes you travelled 30 kilometers, so the rate is 30/75=0.4km/minute

another way is to use the two points to find the slope: m=(30-0)/(75-0)=0.4

lisov135 [29]3 years ago

4 0

Answer:

Option B is correct.

Unit rate = 0.40 km/min

Step-by-step explanation:

Given : A graph with a line running through coordinates (0,0) and coordinates (75, 30).

Here, y represents the distance traveled in km and x represents the number of minutes.

Find the slope of the line:

Slope(m)= $\frac{change in y-axis}{change in x-axis}$ = $\frac{y_2-y_1}{x_2-x_1}$

Given points: (0, 0) and (75, 30)

then;

$m = \frac{30-0}{75-0} = \frac{30}{75} =0.40 km/min$

Since, unit rate is also the slope of the graph.

Therefore, unit rate(in km/min) = 0.40 km/min

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Need a quick answer please

Romashka [77]

Step-by-step explanation:

S is equal to Q

Q= 48.5

there are two angels (S,Q). They equal 48.5

so 48.5x2= 97

all angels together (QRSP) equals 360

you can take the 97 and subtract it from the 360 =263

divide 263 to get the angels for P and R

S= 48.5

Q=48.5

R=131.5

P=131.5

8 0

3 years ago

Mary brought $20 to the skating rink. She paid $5.50 admission and $3.75 to rent skates. She also purchased two bottles of water

Salsk061 [2.6K]

Answer:

20-14.5=5.5

Step-by-step explanation:

7 0

3 years ago

What’s the answer of a multiplying polynomials (3x-1) to the second power and (x+6) to the second power

Vladimir [108]

$9x^4+102x^3+253x^2-204x+36$ is the result of multiplying (3x-1) to the second power and (x+6) to the second power

<h3><u>Solution:</u></h3>

Given that we have to find the result of multiplying polynomials (3x-1) to the second power and (x+6) to the second power

"Second power" means the term is raised to power of 2

Therefore,

We have to multiply $(3x-1)^2 \text{ and }(x+6)^2$

$\rightarrow (3x-1)^2 \times (x+6)^2$

We can use the algebraic identity to expand the above expression

$(a+b)^2 = a^2+2ab+b^2\\\\(a-b)^2=a^2-2ab+b^2$

Applying these in above expression, we get

$\rightarrow ((3x)^2-2(3x)(1)+1^2) \times (x^2+2(x)(6)+6^2)\\\\\rightarrow (9x^2-6x+1) \times (x^2+12x+36)$

Multiply each term in first bracket with each term in second bracket

$\rightarrow 9x^2(x^2)+(9x^2)(12x)+(9x^2)(36)-6x(x^2)-6x(12x)-6x(36) + x^2+12x+36$

Simplify the above expression

$\rightarrow 9x^4+108x^3+324x^2-6x^3-72x^2-216x+x^2+12x+36$

Combine the like terms

$\rightarrow 9x^4+102x^3+253x^2-204x+36$

Thus the above expression is the result of multiplying (3x-1) to the second power and (x+6) to the second power

4 0

3 years ago

A motorboat takes five hours to travel two hundred miles going upstream. The return trip takes four hours going down stream. Wha

Yuri [45]

Answer: $45\ mph$ , $5\ mph$

Step-by-step explanation:

Given

A motorboat takes 5 hours to travel 200 miles upstream and 4 hours to go downstream

Suppose the speed of motorboat in still water and rate of current be x and y respectively.

during upstream

$\Rightarrow 5=\dfrac{200}{x-y}\\\\\Rightarrow x-y=40\quad \ldots(i)$

During downstream

$\Rightarrow 4=\dfrac{200}{x+y}\\\\\Rightarrow x+y=50\quad \ldots(ii)$

Add (i) and (ii) we get

$\Rightarrow 2x=90\\\Rightarrow x=45\ mph$

$\therefore y=5\ mph$

Thus, the speed of boat in still water is $45\ mph$ and rate of current is $5\ mph$

8 0

3 years ago

Solve for z in the literal equation 5/8 (z + 11) = y.

nika2105 [10]

Is there a picture of the problem I can help

4 0

3 years ago