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Yuliya22 [10]
3 years ago
11

NO LINKS WHATSOEVER!!! SPAMMERS WILL BE IMMEDIATELY REPORTED!!! A gardener plants a row of eight trees chosen from three maples,

two oaks, and four birches. In how many ways can he plant the row?
Mathematics
1 answer:
12345 [234]3 years ago
8 0

Answer: 362,880

Step-by-step explanation: At first glance of the question, it doesn't seem that the order matters, which would make it a question of how many combinations there are.  The simple way to look at it is that there are 9 trees and he's planting 8, leaving out 1.  Since there are 9 possible trees to leave out, there are 9 possible combinations of which 8 trees to plant.  

The formula would be 9!/([9-8]!*8!) = 9

If the question is indeed asking for permutations (order matters), since you are choosing 8 out of 9 the formula would be 9!/(9-8)! = 9!/1! = 9! = 362,880

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V+8w=4v,for v<br><br> -m+5n=-2, for n
jok3333 [9.3K]

Answer:

  • v = 8w/3,
  • n = (m - 2)/5.

---------------------------

<h3>Given equations</h3>
  • v + 8w = 4v and - m + 5n = - 2

<h3>Solve the first equation for v</h3>
  • v + 8w = 4v
  • 4v - v = 8w
  • 3v = 8w
  • v = 8w/3

<h3>Solve the second equation for n</h3>
  • - m + 5n = - 2
  • 5n = m - 2
  • n = (m - 2)/5
6 0
1 year ago
Read 2 more answers
Please answer correctly
Phoenix [80]

Answer:

26

Step-by-step explanation:

18 - 2^4 * (-0.5)

Calculate 2 to the power of 4 and get 16.

18−16(−0.5)

Multiply 16 and −0.5 to get −8.

18−(−8)

The opposite of −8 is 8.

18+8

Add 18 and 8 to get 26.

26

8 0
3 years ago
What is the lowest common denominator of 5 and 9
lozanna [386]
It is 45 . Just simply multiply both numbers. You will get the smallest denominator
6 0
3 years ago
Can I please get some help on this...I have tried to many times...
Bezzdna [24]

Answer: A

Step-by-step explanation:

First, the problem is g(f(x)). You would plug in f(x) wherever you see an x in g(x). To find the domain, you take the bottom function, and set it equal to 0.

\sqrt{x-2} =0

When you solve that, you get x=2. You know your domain is x≥2, but there is as asymptote at x=11. That means the graph never reaches x=11, but gets very close. You find that by setting the entire equation equal to 0 and solve from there.

5 0
3 years ago
If the endpoints of the diameter of a circle are (6, 3) and (2, 1), what is the standard form equation of the circle?
Anastasy [175]
If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:

(x,y)=((6+2)/2, (3+1)/2)=(4,2)

Now we need to find the radius....the diameter is:

d^2=(6-2)^2+(3-1)^2

d^2=16+4

d^2=20  since d=2r, r=d/2, and r^2=d^2/4 so

r^2=5

The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:
 
(h,k)=(4,2) from earlier so:

(x-4)^2+(y-2)^2=5
8 0
3 years ago
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