Equaton of a circle that is centerd at (h,k) and radius r is
(x-h)²+(y-k)²=r²
center is (-4,9) and radius is 11
(x-(-4))²+(y-9)²=11^2
(x+4)²+(y-9)²=121
Answer:
7.5h+10=6.25(h+3)
Step-by-step explanation:
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The equation of line perpendicular to given line is:

Step-by-step explanation:
Given equation is:

First of all, we have to find the slope of the given line
So,

Dividing both sides by 2

As the equation is in slope-intercept form, the co-efficient of x will be the slope of the line

As we know that product of slopes of two perpendicular lines is -1
Let m-2 be the slope of line perpendicular to given line

Slope-intercept form is:

putting the value of the slope

Putting the point (3,1) in the equation

Putting the value of b

Hence,
The equation of line perpendicular to given line is:

Keywords: Slope-intercept form, slope
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Given: a | | b, m 2 = m 3
Prove: m 1 = m 3
1. a || b, m∠2 = m∠3
Given
2. m∠1 = m∠2
If lines are ||, corresponding angles are equal.
3. m∠1 = m∠3
Substitution