<em>your answer should be three.</em>
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<em>~iwa-chan</em>
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I'm going to assume that you meant the following:
(x-1)
---------------
x^2-3x+2
Factoring the denominator, we get:
(x-1)
------------
(x-1)(x-2)
Notice that we have x-1 in both the numerator and the denominator. This factor cancels. HOWEVER: x can still not equal 1, which would lead to div. by zero. With the factor x-1 cancelled, we have 1 / (x-2). As x approaches 1 from either side, y approaches 1 / (1-2), or 1 / (-1), or -1. Thus, the limit exists and is -1.
Answer:
Area of the other polygon = 4 in.²
Step-by-step explanation:
Area of the bigger polygon : Area of the smaller polygon = square of the side length of the bigger polygon : square of the corresponding side length of the smaller polygon
Let "x" represent the area of the smaller polygon
Thus, we have:
100/x = 20²/4²
100/x = 400/16
100/x = 25
Cross multiply
25x = 100
Divide both sides by 25
25x/25 = 100/25
x = 4
Area of the other polygon = 4 in.²
First, 9.8 (Gravity) times 3 (time) equals 29.4, which is the velocity after 3 seconds. The kinematic equation for change in position that uses the variables we have is:
delta x= (v)(t) -0.5(acceleration)(time)^2
delta x= 29.4 times (3) - 0.5 (9.8) times 9
delta x= 44.1
100 minus 44.1 equals 55.9, which is the answer for part a.
Tell me if you need any clarification
PART B:
The kinematic equation for this is:
delta x= (initial velocity) times time plus 0.5 (a)(time)^2
100=(0)times(x) plus 0.5 (a)(time)^2
100=0.5(9.8)(x)^2
100=4.9x^2
100/4.9 is approxamitely 20.4.
The squareroot of this is approxamitely 4.5.
4.5 seconds
Tell me if you need any clarification
Y = 2x +13
We know the slope to be 2 because lines that are parallel have the same slope. Then we can solve using slope-intercept form and the known point.
y = mx + b ----> Input known values
7 = (2)(-3) + b ---> Multiple
7 = -6 + b ----> Subtract 3 from both sides
13 = b
Now we can use the y-intercept found and the slope to write the equation above.
