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3 years ago

De acordo com o estudo da equação do 1o grau, determine o valor de x que satisfaz a equação abaixo ?

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

5 0

Answer:

11/5

Step-by-step explanation:

2x+12+4-12x+6

-10x+22

x=22/10

x= 11/5

22/5+12+4=123/5-6

102/5=123/5-30/5

102/5=97/5

102/5-97/5

5/5

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(20 points)Solve the equation cos x = sin (x + 22)

Law Incorporation [45]

Answer:

$\bold{x = 34^\circ}$

Step-by-step explanation:

Given:

$cos x = sin (x + 22^\circ)$

To solve:

The given equation.

Solution:

First of all, let us consider an important property of sine and cosine.

$sin(90^\circ-\theta )=cos\theta$

$cos(90^\circ-\theta )=sin\theta$

We can apply above property to solve for $x$ as per given equation.

$cos x = sin (x + 22^\circ)$

Changing $cosx$ to sine form:

$cosx=sin(90^\circ-x)$

$cosx=sin(90^\circ-x) = sin(x+22^\circ)$

$\therefore 90^\circ-x=x+22^\circ\\\Rightarrow 90^\circ-22^\circ=x+x\\\Rightarrow 2x=68^\circ\\\Rightarrow \bold{x = 34^\circ}$

So, solution to the equation $cos x = sin (x + 22^\circ)$ is:

$\bold{x = 34^\circ}$

7 0

3 years ago

Ingrid spends $120 on car repairs. Which integer represents the amount of money Ingrid must earn in order to create a zero pair?

Julli [10]

Answer: -120

Step-by-step explanation:

this would be the answer because if you take a positive and add it to a negative you get zero if their the additive inverse of the number.

8 0

3 years ago

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Answer this question to get marked as brainliest!!!!!

riadik2000 [5.3K]

Answer:

Isosceles Right Triangle

5 0

3 years ago

Can someone please help me work out the missing angles please I’m struggling

Vladimir [108]

Step-by-step explanation:

a =45°

b=45°

c=30°

d=30°

e=30°

f=30°

total of the angle

90×4=360

6 0

3 years ago

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Please anybody help me please this is so hard that not even I can't solve this I don't pay attention in class

Alla [95]

Answer:

$m\angle B=54^{\circ}$

$m\angle BAD=36^{\circ}$

$m\angle CDA=90^{\circ}$

$BAC=72^{\circ}$

Step-by-step explanation:

Given:

$\overline{AB}\cong \overline{AC},$

$\overline{AD}$ bisects angle BAC

$m\angle C=54^{\circ}$

Triangle ABC is isosceles triangle, because $\overline{AB}\cong \overline{AC}.$ Angles adjacent to the base of isosceles triangle ABC are congruent.

Hence,

$m\angle C=m\angle B=54^{\circ}$

The sum of the measures of all interior angles is 180°, so,

$m\angle B+m\angle C+m\angle BAC=180^{\circ}\\ \\m\angle BAC=180^{\circ}-2\cdot 54^{\circ}=72^{\circ}$

Since $\overline{AD}$ bisects angle BAC, angles BAD and CAD are congruent by definition of angle bisector. So,

$m\angle BAD=m\angle CAD=\dfrac{1}{2}m\angle BAC=\dfrac{1}{2}\cdot 72^{\circ}=36^{\circ}$

AD ia angle bisector in isosceles triangle drawn to the base, so it is the height. Thus, AD and BC are perpendicular. So,

$m\angle CDA=90^{\circ}$

8 0

3 years ago