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Ilya [14]
1 year ago
14

Find the arc length and sectors perimeter of an 85 degree arc of a circle with a finger radius of 4ft

Mathematics
1 answer:
Artist 52 [7]1 year ago
7 0

Answer:

Arc length = 5.93 ft

Perimeter = 13.93 ft

Step-by-step explanation:

85/360*2*π*4 = arc length

5.93411946 ft

Perimeter = 4+4+5.93 = 13.93 ft

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Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con
Ket [755]

Answer:

Step-by-step explanation:

Given that:

H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }

Z = \dfrac{-1}{\dfrac{5.3}{6} }

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

b

For x = 53 and s = 4.6

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }

Z = \dfrac{-2}{\dfrac{4.6}{6} }

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

Conclusion: \  There  \ is \  sufficient \  evidence  \  to \  conclude \  that \mu < 55

c)

For x = 56 and s = 5.0

The test statistics can be computed as:

Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject \mathbf{H_o}

Conclusion: \  There  \ is \  insufficient \  evidence  \  to \  conclude \  that \ \mu < 55

6 0
3 years ago
H=−4.9t2+25t
lina2011 [118]

ANSWER

5

EXPLANATION

The equation that expresses the approximate height h, in meters, of a ball t seconds after it is launched vertically upward from the ground is

h(t) =  - 4.9 {t}^{2}  + 25t

To find the time when the ball hit the ground,we equate the function to zero.

- 4.9 {t}^{2}  + 25t = 0

Factor to obtain;

t( - 4.9t + 25) = 0

Apply the zero product property to obtain,

t = 0 \: or \:  \:  - 4.9t + 25 = 0

t = 0 \:  \: or \:  \: t =  \frac{ - 25}{ - 4.9}

t=0 or t=5.1 to the nearest tenth.

Therefore the ball hits the ground after approximately 5 seconds.

4 0
3 years ago
Read 2 more answers
Which statement correctly describes the diagram?
Komok [63]

Answer:

option 2

Step-by-step explanation:

6 0
3 years ago
Solve. X2 ? 5x = 14 A) x = 0, x = 5 B) x = 0, x = ?5 C) x = 2, x = ?7 D) x = 7, x = ?2
Ymorist [56]
The answer would be letter D.
8 0
3 years ago
Read 2 more answers
33 points!!!!
lakkis [162]
I think it is 4 divided by 5 which equals 4/5 pieces of gum for everyone. (Hope I helped :D and hope I got it right ;D)
4 0
3 years ago
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