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lakkis [162]
1 year ago
13

HELPPP MEEEE MATH 7TH PLS PSLSPLS PLS

Mathematics
1 answer:
allsm [11]1 year ago
6 0

A: Yes, the sum of two sides are greater than the third side.

B: Yes, the sum of two sides are greater than the third side. (Would be an equiilateral triangl.)

C: No, the sum of two sides are less than the third side.

In general, To determine if 3 side lengths are a triangle, use the triangle inequality theorem, which states that the sum of 2 sides of a triangle must be greater than the third side. Therefore, all you have to do is add together each combination of 2 sides to see if it's greater than the third side.

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Suppose that a, b \in \mathbb{Z}a,b∈Z, not both 00, and let d=\gcd(a, b)d=gcd(a,b). Bezout's theorem states that dd can be writt
lara [203]

Answer:

Step-by-step explanation:

Recall that we say that d | a if there exists an integer k for which a = dk. So, let d = gcd(a,b) and let x, y be integers. Let t = ax+by.

We know that d | a, d | b so there exists integers k,m such that a = kd and b = md. Then,

t = ax+by = (kd)x+(md)y = d(kx+my). Recall that since k,  x, m, y are integers, then (kx+my) is also an integer. This proves that d | t.

3 0
3 years ago
What is the difference? Write the number. 60 - 20=
frosja888 [35]
It would be 40.

60 minus 20 = 40

Difference means subtraction
5 0
3 years ago
Read 2 more answers
In the following equation the letter x is known as the:<br> 3x+1=10
hoa [83]

Answer: X = 9

Step-by-step explanation:

First, Take 1 away from 10. 10 - 1 = 9. Then divide 9 by three. 9 divided by three is 3, so X = three.

6 0
3 years ago
What is the answer to 9÷2/3
Karo-lina-s [1.5K]

Answer:

27/2

Step-by-step explanation:

9 : 2/3 =

9 * 3/2 =

(3*9=27)

27/2 Is your answer



6 0
3 years ago
Read 2 more answers
Omg help with my homework PLEASE ASAP. what donu graph and how do i suow my workkkkk whats the answer
Gnoma [55]

Answer:

you have to start with you b which in your problem is 5 so put a point at 5 on the y-axis on your graph. then with the M (the fraction numbers) you have to move either up or down depending if there is a negative number. so yours is 1/2 so then you would start at the 5 point and go up 1 and right 2 then you just keep repeating till you get a few points and can make a line then you just do the same thing for the other equation. start at 3 on the y-axis and then go up 3 and right 4 then just keep repeating till you get a few point and can create a line at the end the lines should cross each other like perpendicular lines

Step-by-step explanation:

hope this helps:)

7 0
2 years ago
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