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denis-greek [22]
3 years ago
12

A building is acquired on January 1,at a cost of 930,000 with estimated useful life of 8 years and salvage value of 73,700

Mathematics
1 answer:
shutvik [7]3 years ago
3 0

Answer:

Year 1 = $196,000

Year 2= $156,800

Year 3= $125,440

Step-by-step explanation:

$980,000 x 20 % = $196,000

Net book value

$980,000 - $196,000 = $784,000 (to be used as base for year 2)

Year 2

$784,000 x 20% = $156,800

Net book value

$784,000 - 156,800 = $627,200

Year 3

$627,200 x 20% = $125,440

Net book value

$627,200 - $125,440 = $501,760

*Salvage value is ignored in computing the yearly depreciation expense under double-declining-balance method. The reason of it is that, it will take longer to depreciate an asset compare to it’s useful life if we deduct salvage value from original cost in depreciating an asset.

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<em>D.) 6 </em>

Step-by-step explanation:

<em>-3+2*6=9</em>

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3 years ago
Please help thank you. i have 2 questions.
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For the first one, the answer is 2. You can only fold it vertically and horizontally. For the second one, the answer is O because any way you turn it, it still looks like O. I hope this helps!
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Setler79 [48]

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I only have number 2 but it's C

Step-by-step explanation:

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What are the values of a and b?
ivann1987 [24]

Answer:

<h2>a = 400/21, b = 580/21</h2>

Step-by-step explanation:

Small triangles are similar. Therefore, the sides are proportional

\dfrac{a}{20}=\dfrac{20}{21}               <em>cross multiply</em>

21a=(20)(20)       <em>divide both sides by 21</em>

a=\dfrac{400}{21}

For b, we can use the Pythagorean theorem:

b^2=\left(\dfrac{400}{21}\right)^2+20^2\\\\b^2=\dfrac{160000}{441}+400\\\\b^2=\dfrac{160000}{441}+\dfrac{176400}{441}\\\\b^2=\dfrac{336400}{441}\to b=\sqrt{\dfrac{336400}{441}}\\\\b=\dfrac{\sqrt{336400}}{\sqrt{441}}\\\\b=\dfrac{580}{21}

3 0
3 years ago
Describe the graph of the function f(x) = x3 − 11x2 + 36x − 36. Include the y-intercept, x-intercepts, and the end behavior.
jenyasd209 [6]
The function is f(x)=x^3-11x^2+36x-36.

To find the x-intercepts, we need to factorize the function. A very good idea is to first try the factors of 36:

f(1)=1-11+36-36, not 0

f(2)=8-44+72-36=-36+72-36=0. Here we have our first root (2).

Now we cad divide f(x) by (x-2) which will give us a quadratic expression, which we can factorize easily (if the discriminant is non negative).

We can also try some other factors of 36. Indeed we can check that 

f(3)=27-99+108-36=135-135=0, 
and
f(6)=216-396+216-36=0.

Thus, f(x)=(x-2)(x-3)(x-6). Note that if we expanded the right hand side expression, the constant term would be the product of the constants 2, 3, 6.

This is the reason why in the first place we looked at the factors of 36 for the possible zeros of f(x).


Thus, the x-intercepts are (2, 0), (3, 0), (6, 0), or 2, 3, 6. 

The y-intercept is f(0), which is -36.


Note that f(0)<f(2) because f(0)=-36 and f(2)=0. This means that at the left side, the graph is coming from - infinity. Similarly, 

we can check that f(10)=1000-1100+360-36=224> f(6). That is, to the right of our rightmost root, the graph is getting larger.

Thus, the end behaviors are: the graph goes to + infinity as x goes to + infinity, 

and it goes to minus infinity as x goes to - infinity.
7 0
3 years ago
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