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2 years ago

I really need help on this math problem, pls anyone that can help?!

Mathematics

2 answers:

Oxana [17]2 years ago

7 0

Equation of line

(0,-2)
(-3,0)

Slope

m=0+2/0-3=-2/3

Perpendicular line's have slope negative reciprocal to each other

Slope of new line=3/2

Equation

in point slope form

y-3=3/2(x+2)
y-3=3/2x+3
y=3/2x+6

mafiozo [28]2 years ago

5 0

Answer:

y = 3/2x + 6

Step-by-step explanation:

Equation of the given line

slope = rise/run = -2/3
y-intercept = (0, -2)
Equation is y = -2/3x - 2

Perpendicular

Slope is the negative reciprocal
m ⇒ -(1/[-2/3]) = 3/2
Intersection point is (-2, 3)

Using Point-slope equation

y - 3 = 3/2 (x + 2)
y - 3 = 3/2x + 3
y = 3/2x + 6

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~PLEASE HELP ASAP OFFERING 10 POINTS~

Aleks [24]

《《 mr. Web boi 》》
product = 200$
hours = 50$

so that means that u buy it, that's -200$ and if he goofs around for hours, that's -50$ for each hour that passes by

answer should be D :)

Hope this helped youu

7 0

4 years ago

Read 2 more answers

The revenue function for a bicycle shop is given by R(x)=x⋅p(x) dollars where x is the number of units sold and p(x)=200−0.4x is

amid [387]

Answer:

maximum revenue is 25000

Step-by-step explanation:

The revenue function for a bicycle shop is given by R(x)=x⋅p(x)

Given $p(x)= 200-0.4x$

$R(x)=x \cdot p(x)$

Plug in p(x) in R(x)

$R(x)=x \cdot 200-0.4x$

$R(x)=200x-0.4x^2$

Now find out the vertex using formula x=-b/2a

a= -0.4, b=200

$x=\frac{-b}{2a} =\frac{-200}{2(-.4)} =250$

Plug in 250 for x in R(x)

$R(x)=200x-0.4x^2$

$R(x)=200(250)-0.4(250)^2=25000$

So maximum revenue is 25000

6 0

3 years ago

The legs of an isosceles triangle have lengths x + 1 and -x + 7 . The base has length 3x - 3. What is the length of the base?

kaheart [24]

Since this is an isosceles triangle, then the lengths of both legs are equal
Therefore,
x+1=-x+7
2x=6
x=3
Therefore, the length of the base is:
3x-3=3(3)-3=6
Then your answer is (A)

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3 years ago

Read 2 more answers

WZ and XR are diameters in circle C. What is the measure of ZWX?

UNO [17]

All work is shown in picture below.