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zhuklara [117]
3 years ago
6

A rectangle has an area of (12m-30n) square units. Its width is 6 units. Factor the expression for the area to find an expressio

n for the length of the rectangle.
Mathematics
1 answer:
garik1379 [7]3 years ago
5 0

Answer: 2m - 5n

<u>Explanation:</u>

Using long division

  <u>    2m - 5n  </u>

6 ) 12m - 30n


width*length = area

6(2m - 5n) = 12m - 30n


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12x&gt;9 (2x-3)-15 solve for x and show steps please.
Verdich [7]

12x > 9(2x-3)-15

distribute the 9

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combine like terms on the right side

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4 0
3 years ago
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Jackson bought 3 pounds of candies for $9.75 What was the price of these candies in dollars per pound?
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9.75 dollars divided by 3 pounds equals 3.25 per pound
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At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

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Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
3 years ago
15 Points!
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Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

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