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zhuklara [117]
3 years ago
6

A rectangle has an area of (12m-30n) square units. Its width is 6 units. Factor the expression for the area to find an expressio

n for the length of the rectangle.
Mathematics
1 answer:
garik1379 [7]3 years ago
5 0

Answer: 2m - 5n

<u>Explanation:</u>

Using long division

  <u>    2m - 5n  </u>

6 ) 12m - 30n


width*length = area

6(2m - 5n) = 12m - 30n


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Two of the statements are true; one is a lie.
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Answer:

Statement 3

Step-by-step explanation:

∠GAF ≅ ∠TAE

Since, there is no relation between these angles,

Therefore, statement is False.

∠TAE and ∠FAH are complementary.

If the sum of the two angles is 90°, pair of angles is said to be complimentary angles.

Therefore, this statement is False.

∠TAF is obtuse.

Measure of obtuse angle is more than 90°

From the given picture, measure of ∠TAF = m∠TAH + m∠HAF

                                                                      = 90° + 50°

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Statement (3) is the correct statement.

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Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

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