Question

(select all that apply)

Answer 1

The simplification of the expression (h² + 9·h - 1) × (-4·h + 3), involves the

multiplication of the terms. The error is therefore;

3. Calculating errors when distributing -1

How can the error in the calculation be found?

The expansion of (h² + 9·h - 1) × (-4·h + 3), is given as follows;

(h² + 9·h - 1) × (-4·h + 3) = -4·h³ + 3·h² - 36·h² + 27·h + 4·h - 3

Which gives;

-4·h³ - 33·h² + 31·h - 3

The calculation is therefore;

$\begin{array}{|c|c|c|c|}&h^2&+9 \cdot h & -1\\-4 \cdot h&-4\cdot h^3&-36\cdot h^2 &4 \cdot h\\+3& 3 \cdot h^2&27 \cdot h&3\end{array}\right]$

The error is therefore, in the distribution of the -1

The correct option is;

3. Calculating errors when distributing -1

Learn more about expansion of polynomial expressions here:

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