Answer: Height at which the wire is attached to the pole is 12 feet.
Explanation:
Since we have given that
Length of the wire = 20 feet
Let the height at which wire is attached to the pole be h
and distance along the ground from the bottom of the pole to the end of the wire be x+4
Now, it forms a right angle triangle so, we can apply "Pythagorus theorem".
But height cant be negative so, height will be 12 feet.
Hence, height at which the wire is attached to the pole is 12 feet.
SOLVE FOR X IN THE DIAGRAM
SUM OF ALL ANGLES ON STRAIGHT LINE IS 180°
ANGLES :- 5x , (x+54°),90
Complete Question:
ABCD Is a rectangle that represents a park.
The lines show all the paths in the park.
The circular path is in the centre of the rectangle and has a diameter of 15m.
Calculate the shortest distance from A to C across the park,using only the lines shown.
*See attachment for the diagram showing the paths in the park.
Answer:
Shortest distance from A to C through the paths only = 102.9 m
Step-by-step explanation:
Length of park = 80 m
Width of park = 50 m
Diameter of the circular path in the center of the park = 15 m
Therefore:
Shortest distance between from A to C across the park if we're to follow only the lines showing the oaths would be = (length of diagonal AC - diameter of the circular path) + (½ of the circumference of the circular path)
✔️Use pythagorean theorem to find AC:
AC = √(80² + 50²) = √8,900
AC = 94.3398113 ≈ 94.34 m (nearest hundredth)
✔️Diameter of circular path = 15 m
✔️½ of the circumference of the circular path = ½(πd)
d = 15 m
½ of the circumference = ½(π*15) = 23.5619449 ≈ 23.56 m (nearest hundredth)
✔️Shortest distance = (94.34 - 15) + 23.56 = 79.34 + 23.56 = 102.9 m
