Answer:
378.5 or just 378
Step-by-step explanation:
This is a linear model with x representing the number of generations that's gone by, y is the number of butterflies after x number of generations has gone by, and the 350 represents the number of butterflies initially (before any time has gone by. When x = 0, y = 350 so that's the y-intercept of our equation.)
The form for a linear equation is y = mx + b, where m is the rate of change and b is the y-intercept, the initial amount when x = 0.
Our rate of change is 1.5 and the initial amount of butterflies is 350, so filling in the equation we get a model of y = 1.5x + 350.
If we want y when x = 19, plug 19 in for x and solve for y:
y = 1.5(19) + 350
y = 378.5
Since we can't have .5 of a butterfly we will round down to 378
The answer is <span>C. 50%.
The theoretical probability has nothing to do with the experiments. So, we will forget results of the experiment and think about theoretical probability. A coin has two sides - head and tail. The probability to get head is 1/2 = 0.5 = 50%. This is because if you toss the coin and you get head, head is one probability of two probability in total (head and tail). The same situation is with tail. Tail is .</span><span>one probability of two probability in total (head and tail).</span>
Answer:
Ramiro is correct.
You cannot identify congruent triangles with only angles Angle-Angle-Angle is not one of the rules of congruence. They could have different sizes with the same angles which doesn't makes them congruent. They are similar though. Once you find the missing angles with the equations 62+39+C=180 and 39+79+X=180 the corresponding angles are congruent. So the triangles are not congruent, but are similar.
Answer:
The actual SAT-M score marking the 98th percentile is 735.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Find the actual SAT-M score marking the 98th percentile
This is X when Z has a pvalue of 0.98. So it is X when Z = 2.054. So
1. 5 and E, 6 and F, 7 and D, 8 and A, 9 and G
