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Shkiper50 [21]
2 years ago
7

In a certain Algebra 2 class of 21 students, 10 of them play basketball and 9 of them

Mathematics
1 answer:
Oliga [24]2 years ago
5 0

Step-by-step explanation:

out of the 21 students, 8 do not play neither basketball nor baseball.

so, 13 students play at least one of these games.

10 play basketball, and 9 play baseball. that would be 19 together. but we have only 13 players.

that means 6 students (19 - 13) must play both games.

remember, a probability is always

desired cases / possible cases

so, when we are looking for the students, who play both games, we have 6 desired cases out of a total of 21.

and the probability to pick one of them is therefore

6/21 = 2/7 = 0.285714286...

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