Answer:
7.14
Step-by-step explanation:
Equation: (x-1)^2=50
Open parentheses: x^2-1^2=50
Solve: x^2-1=50
Addition property: x^2-1+1=50+1
x^2=51
√x^2=√51
x=7.14
<em>Hope this helped!</em>
Hello,
the length of the circomference is 2*π*radius
=2*π*105=659,7344572538565800771551104887... (m)
Answer: Please see attachment.
Solution:
We need to match the column using column proof. Please see the attachment for matching column.
In ΔDOC and ΔBOA
DO=BO (Given)
∠DOC=∠BOA (Vertically Opposite angle)
OC=OA (Given)
∴ ΔDOC ≅ ΔBOA by SAS congruence property
∠1=∠2 and AB=DC By CPCTE
Thus, AB||DC (∠1 and ∠2 are alternate angles equal then lines parallel)
ABCD is a parallelogram. ( If two sides equal and parallel then a parallelogram.
Below is matched table.
DO = OB, AO = OC ⇒ Given
∠ DOC =∠ AOB ⇒ Vertical angles are equal
∆COD ≅ ∆AOB ⇒ SAS CPCTE
∠1 = ∠2, AB = DC ⇒ CPCTE
AB||DC ⇒ If alternate interior angles =, then lines parallel
ABCD is a parallelogram ⇒ If two sides = and ||, then a parallelogram
Please see attachment for figure and matching.
Answer:
That would be cos
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Step-by-step explanation:
Answer:
The area of the base of the pyramid is 109.2 mm.
Step-by-step explanation:
The area of the base of a hexagonal pyramid is given by the area of a hexagon:
Where:
P: is the perimeter
a: is the apothem
We need to find the perimeter and the apothem.
The perimeter is equal to:
Where:
s: is the side of the pyramid
And the apothem is:
So, to calculate the apothem and the perimeter we need to calculate the side of the pyramid. We can find it from the volume of the pyramid:
Where:
h: is the height = 4 mm
V: is the volume = 144 mm³
Then, the side is:
Now, we can find the perimeter and the apothem.
Finally, the area is:
Therefore, the area of the base of the pyramid is around 109 mm.
I hope it helps you!