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viktelen [127]
3 years ago
10

Margaret is making strawberry milkshakes for the kids party. The recipe calls for of a cup of strawberry syrup to make 12 milksh

akes. How many cups of strawberry syrup are needed to make 108 milkshakes.?
Mathematics
2 answers:
VLD [36.1K]3 years ago
8 0
108/12= 9 milkshakes
nikdorinn [45]3 years ago
3 0
12 milkshakes = 1 cup
So 108 divided by 12 is 9. You need 9 cups to make 108 milkshakes.
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I need help.. 
Debora [2.8K]
This is exactly like the one with the 'n's that you posted yesterday.
I guess you didn't get enough help on that one to understand it.

<span><u>7k/8 - 3/4 - 5k/16 = 3/8</u>

3/4 is the same as 6/8.
Add it to each side of the equation:

7k/8         - 5k/16 = 9/8

Multiply each side by 16 :

14k - 5k = 18

Add up the 'k's on the left side:

9k = 18

From this point, you can proceed directly to the numerical value of 'k'
if you need it.<u />

In your question, you said you need help, and I showed you how to
strip the problem down so that the only thing left is ' k = something '.
Giving you the answer is no help.  Nobody actually needs the answer.
</span>


8 0
3 years ago
Read 2 more answers
Find the area of this figure. Please show work if you can!
Yuri [45]
Here is the answer if you can't read my writing than just ask. also if you have any questions about how I got something feel free to ask

8 0
3 years ago
Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
3 years ago
Pleaaseee help, i need the answer asap! (WILL GIVE BRAINLIEST!!)
Setler79 [48]

Answer:

A.

Step-by-step explanation:

Substituting the ordered pairs into the equation. 3x - y/4 = 11

For (3,-8)

3 * 3 - (-8)/4

9- (-2) = 11

For (4, 4)

3 * 4 - 4/4

12 - 1 = 11

Both ordered pairs equals to 11, therefore, they're both solutions to the equation.

8 0
3 years ago
Order of Operation
Sphinxa [80]

<em><u>45(x)-20 </u></em>

x=hours

7 hours

x=7

<em><u>45(7)-20 =295</u></em>

4 0
2 years ago
Read 2 more answers
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