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2 years ago

Select all the rational numbers

Mathematics

1 answer:

Yuliya22 [10]2 years ago

7 0

Answer:

B. 3.14

C. .33

E. 3.46

remember rational number are can be measured from decimals and even fractions.

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Gus has a fish tank that holds 47104710 inches^3 3 of water. He is using a cylinder shaped bucket with a radius of 55 inches and

Darya [45]

Answer: 3 times.

Step-by-step explanation:

Here, The Volume of the gas tank = 4710 $in^3$

While, The radius of the cylindrical shaped bucket = 5 in

And, Height of the cylindrical shaped bucket = 20 in

Therefore, The volume of the bucket = $\pi \times r^2\times h$

= 3.14 × 5 × 5 × 20 = 1570

According to the question, cylinder shaped bucket is used to fill the tank.

Thus, The number of times the bucket will be used to fill the tank

= The Volume of the gas tank/ The volume of the bucket = 4710/1570 = 3

Therefore, The bucket will be used three times to fill the tank.

5 0

3 years ago

At a charity function, $150,045 was donated by three companies A, B, and C in the ratio 7 : 5 : 9. How much money did company B

Svetach [21]

35,725
this is because u can take the ratio 7+5+9=21 then take 150,045/21 which u get 7,145 then time 5 and u get 35,725

8 0

3 years ago

Read 2 more answers

Simplify 6 / (7+3i).

user100 [1]

Answer:

To simplify the following expression: 6 / (7+3i), we're going to multiply and divide the entire expression by (7+3i), as follows:

$\frac{6 (7-3i)}{ (7+3i)(7-3i)} = \frac{42-18i}{58} = 0.72 - 0.31i$

Now, the denominator has NO imaginary numbers.

5 0

4 years ago

Read 2 more answers

Randy divides (2x4 – 3x3 – 3x2 + 7x – 3) by (x2 – 2x + 1) as shown below. What error does Randy make?

jarptica [38.1K]

error is in constant term of quotient

4 0

4 years ago

Read 2 more answers

There are $5$ girls and $5$ boys in a chess club. The club holds a round-robin tournament in which every player plays against ev

Nadusha1986 [10]

To get the total number of games possible, we will use the combination formula.
Total number of games : $_{10}C_{2}$ = 45

Total of 45 games in the whole tournament.

Meanwhile, if there would be boy-versus-boy, we will have $_{5}C_{2}$
The answer is 10.

The fraction for boy-versus-boy game will be 10/45 or 2/9 when simplified.

6 0

3 years ago